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FinnZ [79.3K]
3 years ago
8

Is my answer right? if not break the hard news and give me the right one​

Mathematics
1 answer:
Alisiya [41]3 years ago
8 0
Nope. its y=3x-1. the y intercept is -1, so we put that at the end. And if we take 2 points on the line and use y/x, we get 3/1 or 3, and this is our slope. Also the line is going up so its not negative
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Write each sum using summation notation<br> 12 + 22 + 32 + 42 + ⋯ + 10000^2
Murljashka [212]

Answer:

50,00,70,000

Step-by-step explanation:

The given sequence is Arithmetic Progression.

Arithmetic Progression is a sequence in which every two neighbor digits have equal distances.

Here first we will find the number of terms

For finding the nth term, we use formula

aₙ = a + (n - 1) d

where, aₙ = value of nth term

a = First term

n = number of term

d = difference

Now, In given sequence: 12, 22, 32, 42, ⋯ , 100002

a = 12, d = 10, n = ? and  aₙ= 100002

∴ 100002  = 12 + (n - 1) × (10)

⇒ 99990 = 10(n - 1)

⇒ n = 10000

Now using the formula of Sum of Arithmetic Sequence,

Sₙ = n÷2[2a + (n - 1)d]

⇒ Sₙ = (10000÷2)[2 × 12 + 9999 × 10]

⇒ Sₙ = 5000 [ 24 + 99990]

⇒ Sₙ = 5000 × 100014 = 50,00,70,000

5 0
3 years ago
Select correct answer
Sergio [31]

Answer:

The values of p in the equation are 0 and 6

Step-by-step explanation:

First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p

2

−7p−4=(2p+1)(p−4)

So then the equation looks like:

\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}

2p+1

p

−

(2p+1)(p−4)

2p

2

+5

=−

p−4

5

To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:

\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}

(2p+1)(p−4)

p

2

−4p

−

(2p+1)(p−4)

2p

2

+5

=−

(p−4)(2p+1)

10p+5

Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.

(p^2-4p)-(2p^2+5)=-(10p+5)(p

2

−4p)−(2p

2

+5)=−(10p+5)

Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p

2

−4p)−(2p

2

+5) first:

(p^2-4p)-(2p^2+5)=-p^2-4p-5(p

2

−4p)−(2p

2

+5)=−p

2

−4p−5

-p^2-4p-5=-10p+5−p

2

−4p−5=−10p+5

Combine like terms:

-p^2-4p+0=-10p−p

2

−4p+0=−10p

-p^2+6p=0−p

2

+6p=0

Factor:

p=0, p=6p

7 0
3 years ago
Read 2 more answers
What is the following quotient? 5/√11-√3
kati45 [8]

ANSWER

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

EXPLANATION

The given rational function is

\frac{5}{ \sqrt{11} -  \sqrt{3}}

We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of

\sqrt{11}  -  \sqrt{3}

which is

\sqrt{11}   +  \sqrt{3}

When we rationalize we obtain:

\frac{5( \sqrt{11}  +  \sqrt{3} )}{(\sqrt{11}  - \sqrt{3} )( \sqrt{11}  +  \sqrt{3} )}

The denominator is now a difference of two squares:

(a - b)(a + b) =  {a}^{2}  -  {b}^{2}

We apply this property to get

\frac{5( \sqrt{11}  +  \sqrt{3} )}{( \sqrt{11}) ^{2}    -  ( \sqrt{3}) ^{2}  )}

\frac{5( \sqrt{11}  +  \sqrt{3} )}{11   -  3}

This simplifies to

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

Or

\frac{5 }  {8}\sqrt{11}  + \frac{5 }  {8}\sqrt{3}

8 0
3 years ago
Read 2 more answers
How to write 5/9 + 5/9 as a mixed number ​
velikii [3]

Answer:

You add the numerators so 5 + 5 is 10. So its 10/9. We only added the numerators because the denominators were the same. So then 10/9 simplified by minusing 9 from ten because ten is the denominator the answer is:

 1 1/9

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I am a three-digit number. My second digit is 4 times bigger than the third digit. My first digit is 3 less than my second digit
labwork [276]

Answer:

285

Step-by-step explanation:

use algebra

third is x

second is 4x

first is 4x-3

x+4x+4x-3

9x-3 = x+x+1+x+2

9x-3=3x+3

12x=6, divide x=2

third is 2, sec is 8, first is 5

3 0
3 years ago
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