Answer:
the range is {7,5,1}
Step-by-step explanation:
To find the range, just plug in the domain into the function.
f(-1) = -2(-1) + 5 = 7
f (0) = -2(0) + 5 = 5
f(2) = -2(2) + 5 = 1
Answer:
the total amount of water supplier per hour to the region within a circle of radius R=110 ( that is from distance r, 0<r<110)
![W(R) = 2\pi [1-(R+1)e^{-R}]](https://tex.z-dn.net/?f=W%28R%29%20%3D%202%5Cpi%20%5B1-%28R%2B1%29e%5E%7B-R%7D%5D)
Step-by-step explanation:
if f(r) describes the water supplied at a distance r , the total amount supplied inside a region that goes from 0 until the circle of radius R, is the sum of all f(r) values from 0 until R, that is the integral value over these limits.
The formula deduction can be found in the attached picture
There is an "r" that multiplies e^-r as result of changing from rectangular coordinates to polar ones.(dx*dy --> r*dr*da)
I think you would use the equation 2x+1+33+90=180
Factor out -4
-4(x^3+3x^2-2x-6
Factor out x^2
-4(x^2(x+3)-2x-6)
Factor out -2
-4(x^2(x+3)-2(x+3))
Factor out x+3
-4(x+3)(x^2-2)