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Mathematics

1 answer:

Allushta [10]2 years ago

6 0

Answer:

<h3>FOR THIS PROBLEM I GOT..... (20/r)-(20/s)</h3>

Step-by-step explanation:

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An object is launched from a platform. Its height (in meters), xxx seconds after the launch, is modeled by: h(x)=-5x^2+20x+60h(x

EastWind [94]

It takes 6 seconds for it to hit the ground.

0 = -5x²+20x+60

We can solve this by factoring. First factor out the GCF, -5:

0 = -5(x²-4x-12)

Now we want factors of -12 that sum to -4. -6(2) = -12 an -6+2 = -4:
0 = -5(x-6)(x+2)

Using the zero product property, we know that either x-6=0 or x+2=0; this gives us the answers x=6 or x=-2. Since we cannot have negative time, x=6.

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There would be a hole when x = -4.

If you factor both the top and the bottom, you will see that the factor (x + 4) is in both the numerator and denominator. Therefore, the would be a hole when x = -4 because that would also make the denominator 0.

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