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2 years ago

What is value of x? Enter your answer in the box. x =

Mathematics

2 answers:

Ludmilka [50]2 years ago

8 0

Answer:

x = 10

Step-by-step explanation:

$\dfrac{x+4}{8}=\dfrac{2x+1}{12}$

Cross multiply:

$\implies 12(x+4)=8(2x+1)$

Expand brackets:

$\implies 12x+48=16x+8$

Collect and combine terms:

$\implies 48-8=16x-12x\\\\\implies 40=4x$

Divide both sides by 4:

$\implies x=10$

bogdanovich [222]2 years ago

6 0

$\\ \tt\hookrightarrow \dfrac{x+4}{2x+1}=\dfrac{8}{12}=2/3$

$\\ \tt\hookrightarrow 3(x+4)=2(2x+1)$

$\\ \tt\hookrightarrow 3x+12=4x+2$

$\\ \tt\hookrightarrow x=12-2$

$\\ \tt\hookrightarrow x=10$

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Step-by-step explanation:

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3 years ago

2(x+z) - y x=6 y=8 z=3 need help ASAP PLS

Minchanka [31]

Answer:

Step-by-step explanation:

substitute the given values into the expression

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2 years ago

A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li

hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

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3 years ago

Question 101 points)

maw [93]

Answer:

$\large\boxed{y=-\dfrac{2}{3}x+\dfrac{13}{3}}$

Step-by-step explanation:

$\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-slope\\b-y-intercept\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\===============================$

$\text{We have the point:}\\\\(5,\ 1)\ \text{and}\ (-4,\ 7).\ \text{Substitute:}\\\\m=\dfrac{7-1}{-4-5}=\dfrac{6}{-9}=-\dfrac{6:3}{9:3}=-\dfrac{2}{3}\\\\\text{We have the equation in form:}\\\\y=-\dfrac{2}{3}x+b\\\\\text{Put the coordinates of the point (5, 1) to the equation:}\\\\1=-\dfrac{2}{3}(5)+b\\\\1=-\dfrac{10}{3}+b\qquad\text{add}\ \dfrac{10}{3}\ \text{to the both sides}\\\\\dfrac{3}{3}+\dfrac{10}{3}=b\to b=\dfrac{13}{3}\\\\\text{Finally:}\\\\y=-\dfrac{2}{3}x+\dfrac{13}{3}$

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Ierofanga [76]

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Step-by-step explanation:

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4 years ago

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