Answer:
9/2
Step-by-step explanation:
this is a simple integral function
given limits of interval [a,b] of a continuous function f(t), you can find the area under the curve by using:


using the fundamental theorem of calculus that states the integral of f(x) in the interval [a,b] is = g(a)-g(b), where g(x) is the antiderivative of f(x)
our g(x) = 
g(3)-g(0) = g(3) = 27/2 - 27/3 = 27/2-9 = 9/2
-3
Explanation:
If f(x)=f(-1) then you just fill in -1 where x is.
2*-1-1
-2-1
-3
Answer:
7/10 or 0.7
Step-by-step explanation:
The first step that you need to do is to convert 5.6 to a fraction. 5.6 can be rewritten as
, which is equal to
.To multiply two fractions together, you simply need to multiply together the numerators and then the denominators.
. Hope this helps!
Answer:
D
Step-by-step explanation:
If y = log x is the basic function, let's see the transformation rule(s):
Then,
1. y = log (x-a) is the original shifted a units to the right.
2. y = log x + b is the original shifted b units up
Hence, from the equation, we can say that this graph is:
** 2 units shifted right (with respect to original), and
** 10 units shifted up (with respect to original)
<u><em>only, left or right shift affects vertical asymptotes.</em></u>
Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.
Answer choice D is right.