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aliya0001 [1]
3 years ago
13

Hayden is 59 inches tall and is standing on top of a ladder that is 2 yards tall. In inches, what is the distance from the top o

f Hayden's head to the ground?
Mathematics
2 answers:
bazaltina [42]3 years ago
7 0
One yard is 36 inches, so 36*2=72 and add that to Hayden's height, 72+59=131 inches.

Your answer is 131 inches
Sedbober [7]3 years ago
3 0
131 inches in all i just made sure
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Examine the system of equations.
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For the equation, complete the solution. 7x + y = −18
Alex777 [14]

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Sam invests $6000 in two different accounts. The first account paid 12 %, the second account paid 7 % in interest. At the end of
Lunna [17]

Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

SI = \frac{P \times T \times R}{100}

First account:SI=\frac{x \times 1 \times 12}{100}

Second account : SI =\frac{(6000-x) \times 1 \times 7}{100}

We are given that At the end of the first year he had earned $590 in interest.

So, \frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400

So,the amount in the account at 12% interest is $3400

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8 0
3 years ago
use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

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Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

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Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

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