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GalinKa [24]
3 years ago
11

Help with proofs please

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0

Answer:

B. Division Property of Equality

Step-by-step explanation:

Hope it helps.

You might be interested in
Help evaluating the indefinite integral
Dafna11 [192]

Answer:

\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

General Formulas and Concepts:
<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (cu)' = cu'

Derivative Property [Addition/Subtraction]:
\displaystyle (u + v)' = u' + v'
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:
\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:
\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution/u-solve</em>.

  1. Set <em>u</em>:
    \displaystyle u = 4 - x^2
  2. [<em>u</em>] Differentiate [Derivative Rules and Properties]:
    \displaystyle du = -2x \ dx
  3. [<em>du</em>] Rewrite [U-Solve]:
    \displaystyle dx = \frac{-1}{2x} \ du

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Apply U-Solve:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du
  2. [Integrand] Simplify:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du
  3. [Integral] Rewrite [Integration Property - Multiplied Constant]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du
  4. [Integral] Apply Integration Rule [Reverse Power Rule]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C
  5. [<em>u</em>] Back-substitute:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.

---

Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0
2 years ago
PLEASE HELP, question in image
Mashcka [7]
You have the right answer but for the second part it's 65+10/5=x
4 0
3 years ago
Read 2 more answers
Pls help this is for math ill give a brainly​
olasank [31]

Answer: The last one - 5 1/3 divided by 1/6

Step-by-step explanation:

since you are trying to figure out how much she runs a day, u divide

Hope this helps :)

6 0
3 years ago
22. Solve the system
DaniilM [7]
Equation 1)  x + 6y = 2
Equation 2)  5x + 4y = 36

Multiply all of equation 1 by 5.

1)  5(x + 6y = 2)

Simplify.

1)  5x + 30y = 10
2)  5x + 4y = 36

Subtract equations from one another.

26y = -26

Divide both sides by 26.

y = -1

Plug in -1 for y in the first equation.

x + 6y = 2

x + 6(-1) = 2

Simplify.

x - 6 = 2

Add 6 to both sides.

x = 8

D : (8, -1)

~Hope I helped!~
8 0
3 years ago
Please help show work please
Lubov Fominskaja [6]

Answer:

A

Step-by-step explanation

it hard to explain

7 0
3 years ago
Read 2 more answers
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