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2 years ago

Question in attachment

Mathematics

1 answer:

denis-greek [22]2 years ago

6 0

Answer:

(a) x + y = 63 OR 3x = 63

(b) 21

Step-by-step explanation:

Let Vijay's age be x and Ajay's be y.

Ajay is twice as old as Vijay

==> Ajay's age = 2 × Vijay's age

==> y = 2x

Sum of their ages = 63

==> x + y = 63

Substituting 2x for y:

==> x + 2x = 63

==> 3x = 63

Solving the above-obtained equation:

==> x = 21

Ajay's age = 2 times that of Vijay

==> y = 2x

==> y = 2×21

==> y = 42

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A 90-inch length of ribbon is to be cut into three pieces. The longest piece is to be 30 inches longer than the shortest piece,

Free_Kalibri [48]

Lets name the shortest piece a, the medium b and the longest c

Together they are 90inches
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The longest is 30 inches longer than the shortest
$c = a + 30$
The third piece is half the lenght of the longest
$b = \frac{c}{2}$

So if you place c=a+30 in the other 2 equasions you get

$a + b + (a + 30) = 90 = 2a + b + 30$
And
$b = \frac{30 + a}{2}$
Now if you put this 2 toghether u get
$2a + \frac{30 + a}{2} + 30 = 90$
Multyplied by 2
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Meaning that a=18inches

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$b = \frac{30 + 18}{2}$
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And together they must be 90 so

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3 years ago

Question in attachment​

Question in attachment