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antoniya [11.8K]
2 years ago
15

Question in attachment​

Mathematics
1 answer:
denis-greek [22]2 years ago
6 0

Answer:

(a) x + y = 63 OR 3x = 63

(b) 21

(c) 42

Step-by-step explanation:

Let Vijay's age be x and Ajay's be y.

Ajay is <u>twice</u> as old as Vijay

==> Ajay's age = 2 × Vijay's age

==> <u>y = 2x</u>

<h3>(a)</h3>

<u>Sum</u> of their ages = 63

==> x + y = 63

<em>Substituting</em><em> </em><em>2</em><em>x</em><em> </em><em>for</em><em> </em><em>y</em><em>:</em>

==> x + 2x = 63

==> 3x = 63

<h3>(b)</h3>

<em>Solving the above-obtained equation:</em>

<u>==> x = 21</u>

<h3>(c)</h3>

Ajay's age = 2 times that of Vijay

==> y = 2x

==> y = 2×21

<u>==> y = 42</u>

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Which number is not equal to one of the following expressions? 1,400 x 10
pochemuha
The answer is 140

Explanation:
1,400 x 10= 14,000
140,000\100=1,400
1,400 x 100= 140,000
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2 years ago
The length of the guy why supporting a cell tower is 120 m the guy wire is anchored to the ground at a distance of 80 m from the
Katarina [22]

Complete Question

The length of the guy wire supporting a cell tower is 120 m. The guy wire is anchored to the ground at a distance of 80 m from the base of the tower to the nearest hundredth of a meter how tall is the tower?

Answer:

89.44m

Step-by-step explanation:

We solve this question using the Pythagoras Theorem

This is given as:

Hypotenuse² = Opposite ² + Adjacent ²

Hypotenuse = Length of the guy wire = 120m

Adjacent = Distance from the base of the tower = 80m

Opposite = Height of the building = x

Hence:

120² = x² + 80²

Collect like terms

x² = 120² - 80²

x = √120² - 80²

x = √(8000)

x = 89.4427191 m

Approximately the height of the tower is = 89.44m

6 0
3 years ago
Calculate 0.05181 ÷ 3.14 and write your answer
balandron [24]

Given:

0.05181 ÷ 3.14 = 0.0165

i)  0.02

ii) 0.016

iii) 0.0165

<h3>What is a mathematical expression ?</h3>

In mathematics, an expression or mathematical expression is a finite combination of symbols well formed according to context-dependent rules. Mathematical symbols can be used to define numbers (constants), variables, operators, functions, parentheses, punctuation marks, and groupings that help define the order of operations and other aspects of logical syntax.

Many authors distinguish between an expression and a formula, the first meaning a mathematical object and the second a statement about mathematical objects.

To learn more about mathematical expression, visit;

brainly.com/question/14462529

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5 0
1 year ago
Carlos jogged 5 laps around the school track in 8 minutes. What was his average speed in laps per minute? lap(s) per minute PLEA
aleksklad [387]

Answer:

To solve this problem, you would create two ratios and make them equal to each other, both representing laps:minute or laps/minute! With that being said, laps will be in the numerator, or on top, and minutes will be in the denominator, or the bottom! The first ratio, which we know from the problem, will be 5/8. In order to write the second ratio, we need to come up with something to put in place for what we're solving for. I like to use x. So, we need to find how many laps (x) are run in 1 minute. Remember, laps are on top and minutes are on the bottom. The second ratio would look like x/1. Then we make them equal to each other -> 5/8=x/1. You would then solve this equation by multiplying the right side of the equation by the reciprocal of the denominator! So, it would be 1/1(5/8)=x. Because then multiple the numerators and the denominators -> 1(5)=5 and 1(8)=8! This makes the equation turn into x=5/8! Because x equals the number of laps run in one minute, we can say that Ricky ran 5/8 of a lap in one minute or 0.625 laps in one minute!

Step-by-step explanation:

5 0
3 years ago
rick jogged the same distance on tuesday snd friday, and 8 miles on sunday for a total of 20 miles for the week. solve to find t
saveliy_v [14]

Ricky jogged 6 miles on tuesday and 6 miles on friday

<em><u>Solution:</u></em>

Given that,

Rick jogged the same distance on tuesday and friday

Let "x" be the distance jooged on each tuesday and friday

He also jogged for 8 miles on sunday

Total of 20 miles for the week

Therefore, we frame a equation as,

total distance jogged = miles jogged on tuesday + miles jogged on friday + miles jogged on sunday

20 = x + x + 8

20 = 2x + 8

2x = 20 - 8

2x = 12

x = 6

Thus Ricky jogged 6 miles on tuesday and 6 miles on friday

3 0
2 years ago
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