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Daniel [21]
2 years ago
13

GEOMETRY There are 6 rows of squares

Mathematics
1 answer:
Fiesta28 [93]2 years ago
6 0

Answer: 289

Step-by-step explanation:

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If the math Olympiad club consists of 14 students, how many different teams of 5 students can be formed for competitions?
aliina [53]

Answer:

2

Step-by-step explanation:

5 x 2 = 10

5 x 3 = 15 > 14

therefore...

there are 2 teams of 5

6 0
4 years ago
How do I solve x/8+15=20
bogdanovich [222]

Answer:

x = 40

Step-by-step explanation:

1/8x + 15 = 20

         -15    -15

1/8x = 5

x8      x8

x = 40  

3 0
3 years ago
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PLEASE HELP!
Ivenika [448]

Answer:

(D)Which equation matches the word problem? 24.35+45.65 = m

(D)Curtis withdrew $70 from the ATM.

Step-by-step explanation:

Addition and Subtraction Equations  Assignment

Using a Bar Diagram

8 0
3 years ago
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Which of the following points is the solution of the quadratic equation : 3x² - 5x-2=0​
snow_tiger [21]

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answer in the file

Step-by-step explanation:

4 0
3 years ago
A random sample of 21 observations is used to estimate the population mean. The sample mean and the sample standard deviation ar
stepladder [879]

Answer:

a. CI=[128.79,146.41]

b. CI=[122.81,152.39]

c. As the confidence level increases, the interval becomes wider.

Step-by-step explanation:

a. -Given the sample mean is 137.6 and the standard deviation is 20.60.

-The confidence intervals can be constructed using the formula;

\bar X\pm \ z\frac{s}{\sqrt{n}},

where:

  • s is the sample standard deviation
  • z is the s value of the desired confidence interval

we then calculate our confidence interval as:

\bar X\pm z\frac{s}{\sqrt{n}}\\\\=137.60\pm z_{0.05/2}\times\frac{20.60}{\sqrt{21}}\\\\=137.60\pm1.960\times \frac{20.60}{\sqrt{21}}\\\\=137.60\pm8.8108\\\\\\=[128.789,146.411]

Hence, the 95% confidence interval is between 128.79 and 146.41

b. -Given the sample mean is 137.6 and the standard deviation is 20.60.

-The confidence intervals can be constructed using the formula in a above;

\bar X\pm z\frac{s}{\sqrt{n}}\\\\=137.60\pm z_{0.01/2}\times\frac{20.60}{\sqrt{21}}\\\\=137.60\pm3.291\times \frac{20.60}{\sqrt{21}}\\\\=137.60\pm 14.7940\\\\\\=[122.806,152.394]

Hence, the variable's 99% confidence interval is between 122.81 and 152.39

c. -Increasing the confidence has an increasing effect on the margin of error.

-Since, the sample size is particularly small, a wider confidence interval is necessary to increase the margin of error.

-The 99% Confidence interval is the most appropriate to use in such a case.

7 0
4 years ago
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