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3 years ago

7

Solve the multiplication problem below.

1 answer:

yuradex [85]3 years ago

4 0

Answer:

What even is this???

Step-by-step explanation:

....

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How do I solve 2 2/7 - 1 1/3

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$2\frac{2}{7}-1\frac{1}{3}\\\\find\ LCD(\frac{2}{7};\frac{1}{3})\\\\the\ list\ of\ multiples\ of\ 7:\ 0;\ 7;\ 14;\ \fbox{21};\ 28;...\\the\ list\ of\ multiples\ of\ 3:\ 0;\ 3;\ 6;\ 9;\ 12;\ 15;\ 18;\ \fbox{21};\ 24;...\\\\LCD(\frac{2}{7};\ \frac{1}{3})=21\\\\\frac{2}{7}=\frac{2\times3}{7\times3}=\frac{6}{21}\\\frac{1}{3}=\frac{1\times7}{3\times7}=\frac{7}{21}\\-------------------$

$2\frac{2}{7}-1\frac{1}{3}=2\frac{6}{21}-1\frac{7}{21}=1\frac{21+6}{21}-1\frac{7}{21}=1\frac{27}{21}-1\frac{7}{21}=\boxed{\frac{20}{21}}$

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4 years ago

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Complex numbers what is the square root of -1

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Answer:

1

Step-by-step explanation:

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4 years ago

Temka [501]

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3 years ago

Simplify the signs in the expression -4 + -1

Dima020 [189]

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a person invested $6700 for one year, part at 8%, part at 10%, and the remainder at 12%. the total annual income from these inve

lukranit [14]

Answer:

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

Step-by-step explanation:

step 1

Let

x-----> the amount invested at 8% rate

y-----> the amount invested at 10% rate

z-----> the amount invested at 12% rate

$z=(x+y)+300$ ----> equation A

$x+y+z=6,700$ ----> equation B

substitute equation A in equation B

$x+y+(x+y+300)=6,700$

$2x+2y=6,400$

$x+y=3,200$ -----> equation C

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=1\ year\\ P=\$6,700\\ I=\$716$

substitute in the formula above

$716=x(0.08)+y(0.10)+z(0.12)$

substitute equation A

$716=x(0.08)+y(0.10)+(x+y+300)(0.12)$

$716=0.08x+0.10y+0.12x+0.12y+36$

$716=0.20x+0.22y+36$

$0.20x+0.22y=680$ -----> equation D

step 2

Solve the system of equations

x+y=3,200 -----> equation C

$0.20x+0.22y=680$ -----> equation D

Solve the system by graphing

The solution is the point (1,200,2,000)

see the attached figure

Find the value of z

$z=(x+y)+300$

$z=(1,200+2,000)+300=3.500$

therefore

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

8 0

4 years ago