Help me please I beg of you

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

(c) Here, also 8 computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

3 years ago

Find the 11th partial sum of the summation of negative 7i plus 22, from i equals 1 to infinity.

marta [7]

I think you mean,

$\sum_{i=1}^{\infty}(7i+22)$

You can use the usual formula,

$S_{k}=\frac{k}{2}(a_1+a_k)$

That in this case is,

$S_{11}=\frac{11}{2}(29+99)=704$

Where I have used,

$a_k=7\cdot k +22$

3 0

3 years ago

13. Jane buys a set of 17 spiral notebooks. Each notebook has 95 pages. What is total number of pages?

const2013 [10]

Multiply number of notebooks by number of pages in each one.

17 x 95 = 1615

The answer is 1,615 total pages

5 0

3 years ago

Read 2 more answers

A team of 4 people participates in a 400-yard relay race. each team member runs the same distance. the team completes the race i

umka2103 [35]

Number of people participating in the relay race = 4
Total distance ran by 4 people of a team = 400 yards
Let us assume the distance run by each member = x yards
Then
4x = 400
x = 400/4
x = 100 yards
Total time taken to rum the full distance = 53.2 seconds
Average running time of each person = 53.2/4
= 13.3 seconds.

6 0

3 years ago

Felipe has 3/4 acre of land to use for a vegetable garden. He separates the land into vegetable plots that are each 1/12 acre. H

antiseptic1488 [7]

Answer:

1) The number of vegetable plot Filipe has = 9 vegetable plots

2) A number line with 1/12 divisions will give the number of 1/12 acre vegetable plots as the number of divisions between 0 and 3/4

Step-by-step explanation:

1) The total size of the land Filipe has = 3/4 acre

The size of the vegetable plots to which he separates the land = 1/12 acre

The number of vegetable plot Filipe has = (The total size of the land Filipe has)/(The size of the vegetable plots to which he separates the land )

∴ The number of vegetable plot Filipe has = (3/4)/(1/12) = 9

The number of vegetable plot Filipe has = 9 vegetable plots

2) The number line can be used to model the situation by having the number line that has divisions of 1/12 unit and counting the number of 1/12 divisions between the zero (0) mark and the three quarter (3/4) mark

3 0

3 years ago