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const2013 [10]
2 years ago
7

What is equivalent to n^-10/n^2

Mathematics
1 answer:
denis-greek [22]2 years ago
7 0

Answer:

1/n^12 or n^-12

Step-by-step explanation:

=n^-10 / n^2

=1/n^10 / n^2

=(1/n^10) *(1/n^2)

=1/n^12

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Consider to circular swimming pools.Pool A has a radius of 12 feet and Pool B has a diameter of 7.5 meters which pool has a grea
mamaluj [8]

C = Pi * d  where C = circumference, d = diameter, r = radius

C = 2*pi *r

we need to watch the units since they are different

Pool A

C = 2 * pi * r

C = 2 * pi * 12  = 24 * pi  in feet


Pool B

C = pi * d

change meters to feet

7.5 m * 3.28 ft/ 1 m  = 24.6 ft

C = pi * 24.6  = 24.6* pi  in ft


Pool B had a greater circumference

24.6 * pi > 24 pi


6 0
3 years ago
From the mid-1960s to the early 1990s, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The
daser333 [38]

Answer:

a) 7.68%

b) 3.38%

Step-by-step explanation:

(a) Estimate the percentage of students scoring over 700 in 1967.

The probability that a student scored over 700 in 1967 equals the area under the Normal curve with mean 543 and standard deviation 110 to the right of 700.

In<em> Excel </em> this value is found with the formula

=1-NORMDIST(700,543,110,1)

and in <em>OpenOffice Calc </em>

=1-NORMDIST(700;543;110;1)

<em> (NORMDIST(700;543;110;1) gives the area to the left of 700, so 1-NORMDIST(700;543;110;1) gives the area to the right of 700) </em>

and equals 0.07675

So, the percentage of students scoring over 700 in 1967 was 7.68%

(b) Estimate the percentage of students scoring over 700 in 1994.

The probability that a student scored over 700 in 1994 equals the area under the Normal curve with mean 499 and standard deviation 110 to the right of 700.

In <em>Excel</em>  this value is found with the formula

=1-NORMDIST(700,499,110,1)

and in <em>OpenOffice Calc </em>

=1-NORMDIST(700;499;110;1)

and equals 0.03383

So, the percentage of students scoring over 700 in 1994 was 3.38%

5 0
4 years ago
If someone eats 3/4 of granola bars per week, what fraction of a box do they eat in per day ?
shepuryov [24]

Answer:

in a day (3/4)÷7=3/28

in a year (3/28)×365=39.107

4 0
2 years ago
Tobias is making scones. The recipe calls for 2/3 cup of flour to make 6 scones. What is the unit rate for cups of flour per sco
MA_775_DIABLO [31]

Answer:

A. 1/9 cup of flour per scone.

B. 9 scones per cup of flour.

Step-by-step explanation:

We're given that Tobias uses 2/3 cup of flour makes 6 scones.

A. The unit rate of cup of flour per scone will be the cup of flour used to make a particular number of scones divided by that number of scones. Mathematically,

U. R. = (cup of flour)/(number of scones)

U. R. = (2/3)/6= 2/(3 *6)

U. R. = 2/18 = 1/9 or 0.11 scones per cup of flour.

B. (i) Method 1

Following the same method we used in (A) above, we need to divide the number of scones by the cup of flour used to make said number of scones. Mathematically,

U. R. = (number of scones)/(cup of flour)

U. R. = 6/(2/3) = (6 * 3)/2

U. R. = (6 * 3)/2 = 18/2

U. R. = 9 scones per cup of flour.

(ii) Method 2

Let the number of scones that can be made with 1 cup of flour(Unit rate for number of scones per cup of flour) be x. Then:

2/3 cup of flour = 6 scones

1 cup of flour = x scones

By cross multiplying and solving:

x = (6 * 1) / (2/3)

x = (6 * 3) / 2

x = 18/2 = 9 scones per cup of flour.

6 0
3 years ago
If f(x)=x/3-2 and g(x)=3x^2+2x-6, find (f+g)(x)
iren2701 [21]
Use cymath it might gives you the answer and shows you how to do it step by step.
6 0
3 years ago
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