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const2013 [10]
2 years ago
7

What is equivalent to n^-10/n^2

Mathematics
1 answer:
denis-greek [22]2 years ago
7 0

Answer:

1/n^12 or n^-12

Step-by-step explanation:

=n^-10 / n^2

=1/n^10 / n^2

=(1/n^10) *(1/n^2)

=1/n^12

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Gabriella rented a bike from Jaidee's Bikes. It cost $14 plus $6 per hour. If Gabriella paid $26 total then how many hours did s
RideAnS [48]

Answer:

2 Hours

Step-by-step explanation:

14+6+6 = 26.

You start with 14, and add on 6 which gives you your starting total 20. So that's one hour. then you add another hour, adding on another $6 making the total $26 and two hours of renting time.

4 0
3 years ago
Yet again I still get confused
ryzh [129]
The left side is a half circle.
 The area of a circle is PI x r^2

The diameter of the circle would be the height of the rectangle, given as 10 feet.
 The radius is 1/2 the diameter, so 5 feet.

The area of half the circle is  (3.14 x 5^2) / 2 = 39.25 square feet.

The area of the rectangle is  20 x 10 = 200 square feet.

Total area = 200 + 39.25 = 239.25 square feet.

6 0
3 years ago
The slope of the line below is 3. Use the coordinates of the labeled point to
Makovka662 [10]

The point-slope equation of the line is y - 8 = 3(x - 6)

<h3>How to determine the equation?</h3>

The points are given as:

(x1, y1) = (6, 8)

The slope is given as:

m= 3

The equation is then calculated as:

y - y1 = m(x - x1)

This gives

y - 8 = 3(x - 6)

Hence, the point-slope equation of the line is y - 8 = 3(x - 6)

Read more about linear equations at:

brainly.com/question/11365604

#SPJ1

5 0
1 year ago
True or False:<br> The following system of equations is consistent.
vampirchik [111]

A system of equation is consistent if there is at least one solution. Since this system of equations has a single solution, it is consistent, the answer is true.

6 0
3 years ago
Find an equation of the line that passes through (3,4) and parallel to 4x-2y=5
Alex73 [517]
       4x - 2y = 5
4x - 4x - 2y = -4x + 5
             -2y = -4x + 5
              -2         -2
                y = 2x - 2¹/₂

          y - y₁ = m(x - x₁)
           y - 4 = 2(x - 3)
           y - 4 = 2(x) - 2(3)
           y - 4 = 2x - 6
             + 4        + 4
                y = 2x - 2
4 0
3 years ago
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