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sergiy2304 [10]
3 years ago
7

Searches related to Elon sat on the dock with his fishing rod, when suddenly he felt the rod being pulled down! He reeled in his

catch, causing it to ascend at a constant rate of 0.10, point, 1 meters per second. When it reached the water's surface after 35 seconds, Elon found it was only an old shoe. Graph the shoe's altitude (in meters relative to the water's surface) as a function of time (in seconds).

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0
The graph is attached.

We first graph the point where his catch reached the surface, (35, 0).  Since it travels upward at a constant rate, the graph will be linear.  We also need to know where it starts (what depth it is at when he begins reeling it in).  We can use the formula d=rt as a template for our function.  d would be distance (in our case, depth), r is the rate (speed) and t is the amount of time.

To find how far the catch had to travel to reach the surface, we set up our equation as:
d = 0.1(35) 

This will tell us how much distance it traveled in 35 seconds.  0.1(35)=3.5, so the catch started 3.5m under water.  It then travels up at 0.1 m per second.

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7 pizzas

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7 pizzas

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{( {2}^{8} \times {3}^{ - 5} \times {6}^{0} })^{ - 2} \\ = \frac{1}{ {( {2}^{8} \times {3}^{ - 5} \times {6}^{0} })^{2} } \\ = \frac{1}{ {(256 \times \frac{1}{ {3}^{5} } \times 1 })^{2} } \\ = \frac{1}{ {(256 \times \frac{1}{243} \times 1 })^{2} } \\ = \frac{1}{ ({ \frac{256}{243} })^{2} } \\ = \frac{1}{ \frac{ {256}^{2} }{ {243}^{2} } } \\ = \frac{1}{ \frac{65536}{59049} } \\ = \frac{59049}{65536}
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3 years ago
Calculate the following:<br> -5(-4) =
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The answer would be -9
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Classify each of the power functions based on their end behavior (increasing or decreasing) as x = ∞
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Answer: right side behavior:

              f(x) is Decreasing

             g(x) is Increasing

             h(x) is Increasing

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<u>Step-by-step explanation:</u>

The rules for end behavior are based on 2 criteria: Sign of leading coefficient and Degree of polynomial

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as x → -∞, f(x) → -∞   Decreasing

g(x) = (x + 2)³

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j(x)=\dfrac{1}{2}(-x)^5\implies j(x)=\dfrac{1}{2}(-1)^5(x)^5\implies j(x)=-\dfrac{1}{2}x^5

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as x → +∞, f(x) → +∞  Decreasing

as x → -∞, f(x) → -∞   Increasing

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Answer: The other diagonal has length 10 in.

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