7 students brought lunch from home
ITS TOO SMALL TO SEE THAT PRINT, BUT CAN SOMEONE PLEASE HELP ME ANSWER THIS PROBLEM ON MY PROFILE I JUST POSTED IT AND NO ONE WILL HELP ME!!1
Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Area of a square= l²
= 8×8 = 64 in²
Area of a circle= πr²
= π × 4²
= 50.3 in²
Difference = 64 - 50.3 = 13.7 in²
