Answer:
Choices A and C because B is not a benefit.
Explanation:
Any process to have heat transfer from a cooler to a hotter object as its sole result.
Answer:
![cscx=\frac{1}{sinx}\\\\\2=\frac{1}{sinx} \\\\sinx=\frac{1}{2}>0\\\\Quadrant\ I,\ II \\\\=> x=\frac{\pi}{6} ,\frac{5\pi}{6} \\\\but\ cosx](https://tex.z-dn.net/?f=cscx%3D%5Cfrac%7B1%7D%7Bsinx%7D%5C%5C%5C%5C%5C2%3D%5Cfrac%7B1%7D%7Bsinx%7D%20%20%5C%5C%5C%5Csinx%3D%5Cfrac%7B1%7D%7B2%7D%3E0%5C%5C%5C%5CQuadrant%5C%20I%2C%5C%20II%20%5C%5C%5C%5C%3D%3E%20x%3D%5Cfrac%7B%5Cpi%7D%7B6%7D%20%2C%5Cfrac%7B5%5Cpi%7D%7B6%7D%20%5C%5C%5C%5Cbut%5C%20cosx%3C0%2C%5C%20so%5C%20x%3D%5Cfrac%7B5%5Cpi%7D%7B6%7D%20%5C%20%28Quadrant%5C%20II%29)
I'm not sure what the question is but I guess it asks for theta...
No product results in -1, hence δlmn is NOT a right triangle showing that lydia's assertion is incorrect
<h3>Perpendicular lines</h3>
In order to determine whether triangle lmn is right-angled, we need to determine the slope of lm, ln, and mn first as shown:
For the slope of lm:
![m_{lm} = \frac{2-0}{2-0}\\ m_{lm} =2/2\\m_{lm} =1](https://tex.z-dn.net/?f=m_%7Blm%7D%20%3D%20%5Cfrac%7B2-0%7D%7B2-0%7D%5C%5C%20m_%7Blm%7D%20%3D2%2F2%5C%5Cm_%7Blm%7D%20%3D1)
For the slope of ln:
![m_{ln} = \frac{-1-0}{2-0}\\m_{ln} =-1/2\\](https://tex.z-dn.net/?f=m_%7Bln%7D%20%3D%20%5Cfrac%7B-1-0%7D%7B2-0%7D%5C%5Cm_%7Bln%7D%20%3D-1%2F2%5C%5C)
For the slope of mn:
![m_{mn} = \frac{-1-2}{2-2}\\m_{ln} =-3/0 = \infty\\](https://tex.z-dn.net/?f=m_%7Bmn%7D%20%3D%20%5Cfrac%7B-1-2%7D%7B2-2%7D%5C%5Cm_%7Bln%7D%20%3D-3%2F0%20%3D%20%5Cinfty%5C%5C)
- If any of the two lines is perpendicular, hence the triangle lmn is right-angled.
- To check, we will take the product of the slopes and see if it is equivalent to -1.
Product of slope lm and ln
![m_{lm}\times m_{ln} = 1 \times -1/2\\m_{lm}\times m_{ln} = -1/2](https://tex.z-dn.net/?f=m_%7Blm%7D%5Ctimes%20m_%7Bln%7D%20%3D%201%20%5Ctimes%20-1%2F2%5C%5Cm_%7Blm%7D%5Ctimes%20m_%7Bln%7D%20%3D%20-1%2F2)
Since no product results in -1, hence δlmn is NOT a right triangle showing that Lydia's assertion is incorrect
Learn more on slopes here: brainly.com/question/3493733
The surface area of the smaller solid is found to be 214 square meters.
<h3>What is Surface area?</h3>
The surface area is given as the sum of the area of all the faces of a three-dimensional object.
The same shape has equivalent ratio of the surface area to volume. It is given as:
![\rm \dfrac{\sqrt{area_1}}{\sqrt{area_2}}=\dfrac{\sqrt[3]{Volume_1} }{\sqrt[3]{Volume_2} }](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B%5Csqrt%7Barea_1%7D%7D%7B%5Csqrt%7Barea_2%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7BVolume_1%7D%20%7D%7B%5Csqrt%5B3%5D%7BVolume_2%7D%20%7D)
On considering the power of 6 at both the sides of the equation:
![\rm \dfrac{area_1^2}{area_2^2}=\dfrac{volume_1}{volume_2}](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7Barea_1%5E2%7D%7Barea_2%5E2%7D%3D%5Cdfrac%7Bvolume_1%7D%7Bvolume_2%7D)
Considering area 1 and volume 1 for the larger solid, and area 2 and volume 2 for the smaller solid, substituting the values give:
![\rm\dfrac{(856\;m^2)^3}{(area_^2)^3}=\dfrac{(1680\;m^3)^2}{(210\;m^3)^2}](https://tex.z-dn.net/?f=%5Crm%5Cdfrac%7B%28856%5C%3Bm%5E2%29%5E3%7D%7B%28area_%5E2%29%5E3%7D%3D%5Cdfrac%7B%281680%5C%3Bm%5E3%29%5E2%7D%7B%28210%5C%3Bm%5E3%29%5E2%7D)
By solving the above equation, the area of the smaller solid is found as 214 square meters. Thus, option B is correct.
Learn more about volume, here:
brainly.com/question/3204154
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