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WINSTONCH [101]
3 years ago
8

Complete the sentence: as altitude ________, air pressure, _________.

SAT
2 answers:
BaLLatris [955]3 years ago
6 0
Altitude and air pressure have an inverse relationship so the answer is
A. increases, decreases
mel-nik [20]3 years ago
3 0
It would be c bc i had the same question and that was the answer
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Point e is drawn on the graph so that line ef is parallel to line cd. If the coordinates of point e are (, y), what is the value
netineya [11]

Based on the graph given, it can be deduced from the computation that the value of y will be -8.

Point C is given as (-10 , -2)  and D = (10 , 6)

The Slope of line CD = ( 6 - (-2) /( 10 - (-10) =  8/20  = 2/5

Since EF is parallel to line CD , the slope of EF = 2/5

Equation  y  = (2/5)x  + c

5y = 2x + 5c

It passes through F ( 6 , -4)

= 5(-4) = 2*6  + 5c

= -20 = 12 + 5c

5c = -32

5y = 2x - 32

Point E ( - 4 , y)

5y = 2(-4) - 32

5y = -8 - 32

5y = -40

y = -8

Therefore, the value of y is -8.

Learn more about graphs on:

brainly.com/question/19040584

8 0
2 years ago
F r e e p o i n t s e v e r y o n e a n d c r o w n f o r b e s t h u m o r :'D
Aleks04 [339]

Answer:

YAYYYYYYYY!!!!!!!!!!!

Explanation:

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8 0
3 years ago
Read 2 more answers
Suppose that a 2% increase in price results in a 6% decrease in quantity demanded. Own-price elasticity of demand is equal to​
kodGreya [7K]

Answer:

The correct answer to the following question will be "3".

Explanation:

The given values are:

Percentage demand,

= 6% i.e., .06

Percentage change in the price,

= 2% i.e., .02

Now,

Own-price elasticity of demand will be:

=  \frac{Percentage \ demand}{Percentage \ change \ in \ price}

On substituting the estimated values, we get

=  \frac{.06}{.02}

=  3

8 0
4 years ago
HELP PLEASE!!
LenaWriter [7]

Answer:

I think it is either A or D

4 0
3 years ago
A 40-kilogram mass is moving across a horizontal surface at 5.0 m/s. what is the magnitude of the net force required to bring th
aliina [53]

Answer:

25 N

Explanation:

Use the equation F = m(Vf–Vi) / Δt.

average force = mass (final velocity - initial velocity) / change in time

F = 40 kg(5.0 m/s) / 8.0 s = 200 / 8.0 = 25 kgm / s^2 = 25 Newtons

4 0
2 years ago
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