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Alik [6]
2 years ago
10

Simplify 4a²+1/3a+5+a²+4+1/3a

Mathematics
1 answer:
vladimir2022 [97]2 years ago
7 0

Answer:

5a^2+\frac{2a}{3} + 9

Step-by-step explanation:

Refer to file. Trying something different. Should be easier to read than text format and is easier than mathML.

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What is an equation for the line through (11,-21) with undefined slope​
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Answer:

x=11

Step-by-step explanation:

An undefined slope is a vertical line on a graph. This means it isn't equal to a y-value, but rather an x-value instead. All values of y work for this function, just as long as the x-coordinate is 11.

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Find the first 5 terms of the sequence: an = 4n-1.
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#sol1

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#sol2

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5 0
2 years ago
Verify the trigonometric identities
snow_lady [41]
1)

here, we do the left-hand-side

\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2&#10;\\\\\\\&#10;[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]&#10;\\\\\\&#10;2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)&#10;\\\\\\&#10;\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}&#10;\\\\\\&#10;\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}&#10;\\\\\\&#10;\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}&#10;\\\\\\&#10;\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
8 0
3 years ago
What is the degree measure of an arc 4(pi) ft. long in a circle of radius 10 ft.?
olya-2409 [2.1K]
Hey there!

20*pi/360=4*pi/x solve for x x=360*4*pi/(20*pi)=72 degrees

Your correct answer would be. . . 

\boxed{\boxed{72}}

Hope this helps.
~Jurgen
3 0
3 years ago
Read 2 more answers
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