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Aneli [31]
3 years ago
8

Can anyone help on this?? It’s due tomorrow!!

Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer: BXC =70°

Step-by-step explanation:

XBC= isosceles so XBC=XCB

XBC=55° (isosceles triangle)

BXC+XBC+XCB=180° (angles in a triangle =180°)

BXC=180°- (55°+55°)

BXC=180°-110°

BXC=70°

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Vitek1552 [10]

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8 0
3 years ago
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 71°, a = 27, c = 26
guajiro [1.7K]

We have

SinC/ c  = Sin A / a

Sin 71/ 26 = Sin A / 27

Sin A  = 27 Sin 71 /  26  = about .982

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Sin-1(.982)  = A  = 79. 08°

Then angle B = 180 - 71 - 79.08 = 29.92°

And b is given by

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b = 26sin29.92/sin71 =  about 13.72

But A could also be an obtuse angle = 180 - 79.08 =  100.92°

So we have

B = 180 - 71 - 100.92 = 8.08°

And we have

b / sin 8.08  = 26/sin71

b = 26sin8.08/sin 71 = 3.865

8 0
3 years ago
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