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yaroslaw [1]
2 years ago
13

Which expression is equivalent 8(2s + 6)

Mathematics
2 answers:
malfutka [58]2 years ago
8 0

Answer:

The answer is 16s+48 because you have to multipy everything.

zvonat [6]2 years ago
5 0

Answer:

16s + 48

Step-by-step explanation:

8(2s + 6) ← multiply each term in the parenthesis by 8

= 16s + 48

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For tall heterozygotes with antennae, the offspring are:
Misha Larkins [42]

Recombinant frequency between T and A is 12%

<u>Explanation:</u>

<u></u>

Two characters are considered - height and antennae

Traits of height - Tall and Dwarf

Traits of antennae - Antennae and No antennae

<u>Given:</u>

<u />

Tall-antennae (46) and dwarf-no antennae (42) are the wild type.

Dwarf- antennae (7) and tall- no antennae (5) are the recombinants.

Total possibilities = 100

Recombinant frequency = \frac{7}{100} + \frac{5}{100}

Recombinant frequency = \frac{12}{100}

Recombinant frequency in percentage = \frac{12}{100} X 100 = 12%

Therefore, recombinant frequency between T and A is 12%

8 0
3 years ago
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irina1246 [14]
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5 0
3 years ago
The church is how many people have signed up to go on a field trip each day 62 students are allowed to go on the field trip on w
Charra [1.4K]

Answer:

Step-by-step explanation

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7 0
3 years ago
Suppose that J and K are points on the number line. If JK=12 lies at 3 , where could K be located? If there are several location
zmey [24]

Answer:

15, -9

Step-by-step explanation:

It is given that J and K are points on the number line. J lies at 3 and JK=12.

We kneed to find the location of K.

A number line is a straight line with numbers placed at equal intervals and extended infinitely in any direction.

If K lies on the left side of J then the location of K is

3 + 12 = 15

If K lies on the right side of J then the location of K is

3 - 12 = -9

The locations of K are defined by the below number.

Therefore the locations of K are 15 and -9.

8 0
3 years ago
A 32 foot tall tree casts a shadow that is 48 feet long How far away from the tree is a 6 ft person
dedylja [7]

Answer:

39 feet

Step-by-step explanation:

In the attached diagram

The height of the tree = AB

The height of the man =DE

The length of the shadow =BC

We want to determine how far away from the tree the person is, i.e. |AD|=y

In Triangle ABC

Tan \theta=\dfrac{32}{48}

In Triangle CED

Tan \theta=\dfrac{6}{48-y}

Therefore:

Tan \theta=\dfrac{32}{48}=\dfrac{6}{48-y}\\\dfrac{32}{48}=\dfrac{6}{48-y}\\$Cross Multiply\\32(48-y)=48*6\\1536-32y=288\\32y=1536-288\\32y=1248\\Divide both sides by 32\\y=39

Therefore, the distance of the man from the tree is 39 feet.

7 0
3 years ago
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