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Gnom [1K]
2 years ago
15

What is the surface area of the right prism below?

Mathematics
2 answers:
-Dominant- [34]2 years ago
3 0

Answer:

120 sq. units

plus them all and add 100

ANEK [815]2 years ago
3 0

Answer:

156 sq. units is the answer

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Which inequality is true?
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D. Will be the correct answer
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Pierce is making a rectangular frame for a photo collage that has a perimeter of 72.2 72.2 inches. The length of the frame is 20
Allushta [10]

Answer:

P = 2x+2y   (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

P-2y = 2x

\frac{P-2y}{2} =x

And replacing we got:

x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in

And the width for this case would be 15.8 in

Step-by-step explanation:

For this case we know that the photo is rectangular. Let's define:

x = the width,  y= the length

And we know that the perimeter is given by:

P = 2x+2y   (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

P-2y = 2x

\frac{P-2y}{2} =x

And replacing we got:

x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in

And the width for this case would be 15.8 in

4 0
3 years ago
Mia and her 3 friends went out for dinner at a restaurant. Total bill was $ 65.12. All friends are going to divide the bill. How
eduard

Answer:

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Step-by-step explanation:

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The equation tan^2 x+1=sec^2 x is an identity true or false
Solnce55 [7]

Answer:

tan²x + 1 = sec²x is identity

Step-by-step explanation:

* Lets explain how to find this identity

∵ sin²x + cos²x = 1 ⇒ identity

- Divide both sides by cos²x

∵ sin x ÷ cos x = tan x

∴ sin²x ÷ cos²x = tan²x

- Lets find the second term

∵ cos²x ÷ cos²x = 1

- Remember that the inverse of cos x is sec x

∵ sec x = 1/cos x

∴ sec²x = 1/cos²x

- Lets write the equation

∴ tan²x + 1 = 1/cos²x

∵ 1/cos²x = sec²x

∴ than²x + 1 = sec²x

- So we use the first identity sin²x + cos²x = 1 to prove that

 tan²x + 1 = sec²x

∴ tan²x + 1 = sec²x is identity

8 0
3 years ago
Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
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Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
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