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bagirrra123 [75]
3 years ago
10

Choose the following ratios as a decimal: 20 correct out of 25 problems

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

.8

Step-by-step explanation:

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What is the domain of the square root function graphed below
Lina20 [59]

Answer:

Dominio de una Raíz cuadrada

Cuando tenemos una raíz, para estudiar su existencia debemos saber que una raíz existe si y solo sí el radicando (lo que está dentro de la raíz) sea mayor o igual a cero.

Por lo tanto deberemos estudiar el signo de lo que se encuentra dentro de la raíz; y determinar las zonas positivas y las raíces que son las zona de existencia de la función raíz o dominio de esta función.

Step-by-step explanation:

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5 0
3 years ago
1.Simplify the following Expression<br> a. 5y^2+ 3y – 13 + 6x – 3y + 6y^2
insens350 [35]

Simplified expression is 11y² + 6x - 13

Step-by-step explanation:

  • Step 1: Simplify 5y² + 3y - 13 + 6x - 3y + 6y²

5y² + 3y - 13 + 6x - 3y + 6y² = 11y² + 6x - 13

6 0
3 years ago
Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%
ivolga24 [154]

Answer:  

<em>a.  The system of equations that models the situation is....</em>

<em>     0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40</em>

<em>b.  The solution to the system:  x = 2 and y = 4 </em>

<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50              mixture is 4 pounds.</em>

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is  x pounds and the amount of 50/50 mixture is  y pounds.

So, the amount of peanuts in 80/20 mixture = 0.80x pound and the amount of almonds in 80/20 mixture =0.20x pound.

And the amount of peanuts in 50/50 mixture =0.50y pound and the amount of almonds in 50/50 mixture =0.50y pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture =(6\times 0.60)=3.60 pounds

and the amount of almonds in that mixture =(6 \times 0.40)= 2.40 pounds.

So, the system of equations will be.........

0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)

Subtracting equation (2) from equation (1), we will get.....

(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2

Now, plugging this x=2 into equation (1), we will get......

0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

7 0
3 years ago
How do you solve 9 - x = 10 using algebraic operations?
vfiekz [6]
9 - x = 10\\&#10;-x=1\\&#10;x=-1
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What is (7x3+3)+(4+2) hurry p[ease
allsm [11]
(7x3+3) + (4+2) is 30
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4 years ago
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