We are given
arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103
so, first term is 124
u(1)= 124
now, we can find common difference
now, we can find kth term
now, we can plug values
and we get
u(k) must be negative
so,
now, we can solve for k
so, it's closest integer value is
..............Answer
Answer:
4m
Step-by-step explanation:
m+m+m+m
There is an implied 1 in front of each term
1m+1m+1m+1m
Factor out the m
(1+1+1+1)m
4m
Answer:
The mean is 6.6
The median is 16
mode is 18
Step-by-step explanation:
I'm not sure if this is tight but yeah:)
X^2 + 5x = -2
x^2 + 5x + 2 = 0
x = -b (+-) sqrt (b^2 - 4ac) / 2a
a = 1, b = 5, and c = 2
x = -5 (+-) sqrt (5^2 - 4(1)(2)) / 2(1)
x = -5 (+-) sqrt (25 - 8) / 2
x = -5 (+-) sqrt (17) / 2
answer is : negative 5 plus or minus the square root of 17 divided by 2
What kind of math is it? Just wondering so that I can help you
