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Bumek [7]
2 years ago
6

30 is 10 times as much as

Mathematics
2 answers:
lesya [120]2 years ago
8 0

Hi!I don't really understand what you mean I am thinking you are saying 30×10 if so the answer is 300

Alex Ar [27]2 years ago
4 0

Answer:

Hi, 30 is 10 times as=30×10=300

Step-by-step explanation:

If you multiple with 30×10 we get as product is 300

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Which equations describes a line that has a y-intercept of 4 and a slope of 3?
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Hello there!

If a line has a slope of 3 and a y-intercept of 4, its equation looks like this:

y=3x+4

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SilentNature

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2 years ago
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Find the GCF of the monomials: 32x^2 and 24x^2y
aev [14]

Answer:

8x^2

Explanation:

First, do prime factorization of each of the coefficients:

32   ⇒   2^5

24   ⇒   2^3, 3

The greatest common factor (GCF) of the coefficients is 2^3 = 8.

Next, find the GCF of the variables:

x^2

x^2, y

The GCF of the variables is x^2.

Finally, multiply the GCF of the coefficients by the GCF of the variables to get:

8x^2

4 0
1 year ago
A fire is sighted Due West of Lookout A. The bearing of the fire from Lookout B, 6.5 miles due south of A, is North 35°34'W. How
KonstantinChe [14]
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4 0
3 years ago
The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
Brilliant_brown [7]

Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

7 0
2 years ago
Find the sum.<br> 13(9−6m)+14(12m−8) =
allochka39001 [22]

Answer:

5+90m

Step-by-step explanation:

117 - 78m + 168m - 112


117- 112 = 5

-78m + 168m= 90m


5+90m

7 0
3 years ago
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