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GrogVix [38]
3 years ago
5

It costs $50 per hour to rent a jet ski. The total cost of a jet ski rental includes a flat fee plus an hourly fee. After 5 hour

s, the total cost is $265. Write an equation that represents the total cost y after x hours.
Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

50x + 15 = y

Step-by-step explanation:

You have to find the flat cost by multiplying the 50 by 5, and then plugging that in for your first constant, and then solve by subtracting that from 265 to get your flat rate, and then put it all together. (see attachment for details)

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balu736 [363]

Answer:

5. LCM of 7 and 14: <u> </u><u> </u><em><u>1</u></em><em><u>4</u></em><em><u>. </u></em>

multiples of 7: <u> </u><u> </u><u>7</u><u>,</u><u> </u><u>1</u><u>4</u><u> </u>

multiples of 14: <u> </u><u>1</u><u>4</u><u> </u>

LCM of 8 and 12: <u> </u><u> </u><em><u>2</u></em><em><u>4</u></em><em><u>. </u></em>

multiples of 8: <u> </u><u> </u><u>8</u><u>,</u><u> </u><u>1</u><u>6</u><u>,</u><u> </u><u>2</u><u>4</u><u> </u>

multiples of 12: <u> </u><u> </u><u>1</u><u>2</u><u>,</u><u> </u><u>2</u><u>4</u><u> </u>

Step-by-step explanation:

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5 0
3 years ago
. Could someone please explain this to me in detail. I am very confused. Thank you so much!. . A candle is 17 inches tall after
andrew-mc [135]

The generic equation of the line is:

H-H0 = m (T-T0)

Where,

m: slope of the line

(T0, H0): ordered pair belonging to the line.

The slope of the line is:

m =\frac{H2-H1}{T2-T1}

Substituting values we have:

m =\frac{15-17}{5-3}

Rewriting:

m =\frac{-2}{2}

m = -1

Then, choosing an ordered pair we have:

(T0, H0) :( 5, 15)

Substituting values we have:

H-15=-(T-5)

Rewriting the equation:

H-15=-T+5

H=-T+5+15

H=-T+20

Then, for 8 hours we have:

H=-8+20

H=12

Answer:

a linear equation to model the relationship between height H of the candle, and T time is:

H=-T+20

the candle will be 12 inches after burning 8 hours

7 0
3 years ago
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Answer:

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Step-by-step explanation:

1/3+1/5+1/2

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Is this HL, SSS, NOT CONGRUENT OR SAS
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61.6 millimeters is the area
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