The volume of a cone varies jointly with the area of the base and the height of the cone.

where
V = volume
k = constant of proportionality
A = area of the base
h = height of the cone
The given info is for A = 27, and h = 6, then V = 54 (all using appropriate units for area, length, and volume, respectively.)
Now we can find k, the constant of proportionality.
V = kAh
54 = k * 27 * 6
k = 54/(27 * 6)
k = 1/3
The formula is

Now we use the second set of info, the height and the volume, and we find the area of the base.




Answer: the area of the base is 31 cm^2
I think the answer is J
Y = 7
You could also use
Geo calculator to make it easier.
You’ll just have to write the point and the choices.
From the description given for the triangle above, I think the type of triangle that is represented would be a right triangle. This type of triangle contains a right angle and two acute angles. In order to say or prove that it is a right triangle, it should be able to satisfy the Pythagorean Theorem which relates the sides of the triangle. It is expressed as follows:
c^2 = a^2 + b^2
where c is the hypotenuse or the longest side and a, b are the two shorter sides.
To prove that the triangle is indeed a right triangle, we use the equation above.
c^2 = a^2 + b^2
c^2 = 20^2 = 10^2 + (10sqrt(3))^2
400 = 100 + (100(3))
400 = 400
5 times a number plus two is 17
5(x) + 2 = 17
isolate the x, do the opposite of PEMDAS
(Note: What you do to one side you do to the other, because of equal sign)
5x + 2 (-2) = 17 (-2)
5x = 15
5x/5 = 15/5
x = 3
hope this helps
Answer:
Adults = x
Students = y = x + 40. 40 more student than adult
Adult = $8, Student = $6
Total for Adults = 8*x = 8x
Total for students = 6*y = 6y
Total = $1920
8x + 6y = 1920
Hence system of equations are:
y = x + 40
8x + 6y = 1920