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yaroslaw [1]
4 years ago
6

I bought a box from the post office that has a volume of 24 cubic centimeters,

Mathematics
1 answer:
Ierofanga [76]4 years ago
6 0

A I hope it can help youb

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Consider the following equation of the form dy/dt = f(y)dy/dt = ey − 1, −[infinity] < y0 < [infinity](a) Sketch the graph
kotegsom [21]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

a) The graph of  f(y) versus y. is shown on the second uploaded image

b) The critical point is at y = 0  and the solution is asymptotically unstable.

c)The phase line is shown on the third uploaded image

d) The sketch for the several graphs of solution in the ty-plane  is shown on the fourth uploaded image

Step-by-step explanation:

Step One: Sketch The Graph of  f(y) versus y

Looking at the given differential equation

       \frac{dy}{dt} = e^{y} - 1 for -∞ < y_{o} < ∞

 We can say let \frac{dy}{dt} = f(y) =e^{y} - 1

Now the dependent value is f(y) and the independent value is y so to sketch is graph we can assume a scale in this case i cm on the graph is equal to 2 unit for both f(y) and y and the match the coordinates and after that join the point to form the graph as shown on the uploaded image.

Step Two : Determine the critical point

   To fin the critical point we have to set   \frac{dy}{dt} = 0

       This means e^{y} - 1 = 0

                          For this to be possible e^{y} = 1

                          which means that  e^{y} = e^{0}

                          which implies that y = 0

Hence the critical point occurs at y = 0

meaning that the equilibrium solution is y = 0

As t → ∞, our curve is going to move away from y = 0  hence it is asymptotically unstable.

Step Three : Draw the Phase lines

A phase line can be defined as an image that shows or represents the way an ODE(ordinary differential equation ) that does not explicitly depend on the independent variable behaves in a single variable. To draw this phase line , draw the y-axis as a vertical line and mark on it the equilibrium, i.e. where  f(y) = 0.

In each of the intervals bounded  by the equilibrium draw an upward

pointing arrow if f(y) > 0 and a downward pointing arrow if f(y) < 0.

      This phase line would solely depend on y does not matter what t is

On the positive x axis it would get steeper very quickly as you move up (looking at the part A graph).

For  below the x-axis which stable (looking at the part a graph) we are still going to have negative slope but they are going to be close to 0 and they would take a little bit longer to get steeper  

Step Four : Draw a Solution Curve

A solution curve is a curve that shows the solution of a DE (deferential equation)

Here the solution curve would be drawn on the ty-plane

So the t-axis(x-axis) is its the equilibrium  that is it is the solution

If we are above the x-axis it is going to increase faster and if we are below it is going to decrease but it would be slower (looking at part A graph)

5 0
3 years ago
Alan has read ​10% of a book. He has 81 more pages to finish. How many pages are there in the​ book?
rewona [7]

Answer:

90

Step-by-step explanation:

100%-10%=90%

90%->81

10%->9

100%->9+81=90

6 0
3 years ago
Find the volume of a right circular cone that has a height of 6.7 in and a base with a diameter of 8.8 in. Round your answer to
N76 [4]

Answer: 135.8

Step-by-step explanation:

the formula for this is πr²H/3

π4.4^2x6.7/3

407.5/3

135.8

4 0
3 years ago
Which expression is equivalent to<br> (r^7)^6
mr_godi [17]

Answer:

r^42

Step-by-step explanation:

Just multiply the two exponents together:

(r^7)^6 = r^42

4 0
3 years ago
What does 9/5 + 14/12 equal
fenix001 [56]

Answer:

53/50

Step-by-step explanation:

9/15 + 14/12

Simplify.

9/15 + 7/6

Make denominators equal.

54/90 + 105/90

Add fractions since denominators are equal.

159/90

Simplify.

= 53/50

7 0
3 years ago
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