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irinina [24]
3 years ago
5

Find the area of the regular 15-gon with radius 10mm.

Mathematics
1 answer:
Nady [450]3 years ago
6 0

318.83484250503 mm^2

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Ann's first option is a plot of land adjacent to a current park.
oksian1 [2.3K]

Given:

The equation for the area of the first option is:

x^2+200x=166400

Where x is the side length of the current square park.

To find:

The side length of the current square park.

Solution:

We have,

x^2+200x=166400

It can be written as:

x^2+200x-166400=0

Splitting the middle term, we get

x^2+520x-320x-166400=0

x(x+520)-320(x+520)=0

(x-320)(x+520)=0

x=320,-520

We know that the side length of a park cannot be negative. So, the only possible value of x is 320.

Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.

4 0
3 years ago
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Vesna [10]

Answer:

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3 0
3 years ago
. A parcel delivery service lowered its A parcel delivery service lowered its prices and finds that it has delivered twice as ma
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6 0
2 years ago
What is the value of f(x) = 2 • 2^x for f(–2)? Will Give brainliest answer!!!
Sedbober [7]
For f(-2), x will equal -2.

Plug the x-value into the equation:

2 \times 2^{-2}

A negative exponent means that the term turns into a fraction, with 1 as the numerator and the positive exponent as the denominator. 
Solve 2^(-2):

2^{-2} =  \frac{1}{2^{2}} =  \frac{1}{4}

Solve the problem:

2 \times \frac{1}{4} = \frac{1}{2}

f(-2) will equal 1/2.
5 0
3 years ago
5
AveGali [126]

Answer:

Total time taken by walking, running and cycling = 22 minutes.

Step-by-step explanation:

Let the speed of walking = x

As given,

The distance of walking = 1

Now,

As Time = \frac{Distance }{Speed}

⇒ Time traveled by walking = \frac{1}{x}

Now,

Given that - He runs twice as fast as he walks

⇒Speed of running = 2x

Also given distance traveled by running = 1

Time traveled by running = \frac{1}{2x}

Now,

Given that - he cycles one and a half times as  fast as he runs.

⇒Speed of cycling =  \frac{3}{2} (2x) = 3x

Also given distance traveled by cycling = 1

Time traveled by cycling = \frac{1}{3x}

Now,

Total time traveled = Time traveled by walking + running + cycling

                                = \frac{1}{x} +  \frac{1}{2x} + \frac{1}{3x}

                                = \frac{6+3+2}{6x} = \frac{11}{6x}

If he cycled the three mile , then total time taken = \frac{1}{3x} + \frac{1}{3x} + \frac{1}{3x} = x

Given,

He takes ten minutes longer than he would do if he cycled the three miles

⇒x + 10 = \frac{11}{6} x

⇒x - \frac{11}{6} x = -10

⇒-\frac{5}{6}x = -10

⇒x = \frac{60}{5} = 12

⇒x = 12

∴ we get

Total time traveled by walking + running + cycling = \frac{11}{6} x = \frac{11}{6} (12) = 11 (2) = 22 min

7 0
3 years ago
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