All categories

3 years ago

Please show your work! thank you

Mathematics

1 answer:

Bingel [31]3 years ago

6 0

You want to write them both into slope intercept form (y=mx+b) so the first one is y=2x-9/2. For the second one you can start converting them until you get y=3x+kx+2 so you need to find the value of K that adds to to equal to 2 because parallel lines have the same slope so k would = -1

You might be interested in

An art gallery is a 6 story square pyramid with base are 1/2 acre ( 1 acre =n4840 yd, 1 story = 10ft) . Estimate the volume in c

zzz [600]

An art gallery is a 6-story square pyramid with base area of half an acre. Estimate the volume in cubic yards of the art gallery. In your calculations, use 1 acre = 4840 yd2 and 1 story = 10 ft.

7 0

3 years ago

What is the answer to the question?

taurus [48]

A=55 hope I helped :)

7 0

3 years ago

The price of a pizza plus 12% delivery charge comes to a total cost of $17.92. What was the price of the pizza?

Leya [2.2K]

Answer:

i believe the answer is 14.93 dollars.

Step-by-step explanation:

3 0

3 years ago

Pleaseee help!!!!!!!!!

NemiM [27]

Answer:

Step-by-step explanation:

Got it right

5 0

3 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{12},0)(± 12 ,0)left parenthesis, plus min

lora16 [44]

Answer:

$\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}$

Step-by-step explanation:

Given that :

the foci of the ellipse is (±√12,0) and C0-vertices are (0,±√37)

The foci are (-C,0) and (C ,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so C0-vertices are (0,±√37)

The given focus C = ae = √12

Given co-vertices ( minor axis) (0,±b) = (0,±√37)

b= √37

We can therefore express the relation between the focus and semi major axes and semi minor axes as:

$\mathbf{c^2 = a^2 - b^2 } \\ \\ \mathbf{a^2 = c^2 + b^2 } \\ \\ \mathbf{c^2 = ( \sqrt12)^2 - (\sqrt 37)^2 } \\ \\ \mathbf{c^2 = 49 } \\ \\ \mathbf{c = \sqrt{49 }}$

The equation of ellipse formula is:

$\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

and we know that $\mathbf{a=\sqrt{49} \ \ and \ \ b=\sqrt{37}}$

Thus ; the equation of the ellipse at the origin is

$\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}$

3 0

4 years ago