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il63 [147K]
2 years ago
14

Find the value for x? x+3 3 2 x

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
7 0
The value is 3 I think I hope it helps
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Can anyone simplify 2d-7=11d+26? Or any of the questions for that matter?
Flura [38]
2d-7=11d+26
-2d-26=-2d-26
-33/9=9/9d
d= -33/9
d= - 11/3
Is this what you're asking for?
4 0
3 years ago
Help please...........
Angelina_Jolie [31]

Answer:

its d

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve for x<br> 1/4 x^3 = -27/4​
ludmilkaskok [199]

do u still need the answer or no cuz its kinda long

5 0
3 years ago
Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How
HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that \mu = 5.2r, in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

P(X \geq 1) = 1 - P(X = 0) = 0.99

Thus:

P(X = 0) = 1 - 0.99 = 0.01

We have that:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}

Then

e^{-5.2r} = 0.01

\ln{e^{-5.2r}} = \ln{0.01}

-5.2r = \ln{0.01}

r = -\frac{\ln{0.01}}{5.2}

r = 0.89

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0
3 years ago
Write the equation g(x) in vertex form of a
DerKrebs [107]

The equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Given a  quadratic function for the transformations given  the function f(x) = x²

If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value

  • Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)

Hence the equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Learn more here: brainly.com/question/15381183

8 0
2 years ago
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