Question

Find the area of the triangle with the given base and height. b = 3 m and h = 10 1/2 m

Answer 1

Statement:

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

To find out:

The area of the triangle.

Solution:

• Given, base = 3m, height = $10 \frac{1}{2}$m
• We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

• Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$

Answer:

The area of the triangle is $\sf \: 15 \frac{3}{4} {m}^{2}$

Hope you could understand.

If you have any query, feel free to ask.

Answer 2

Answer:

Area of triangle = $\boxed{\sf{15\dfrac{3}{4}}}$ m².

Step-by-step explanation:

Here's the required formula to find the area of triangle :

$\longrightarrow{\pmb{\sf{Area_{(\triangle)} = \dfrac{1}{2} \times b \times h}}}$

• △ = triangle
• b = base
• h = height

Substituting all the given values in the formula to find the area of triangle :

$\twoheadrightarrow{\sf{Area_{(\triangle)} = \dfrac{1}{2} \times b \times h}}$

$\twoheadrightarrow{\sf{Area_{(\triangle)} = \dfrac{1}{2} \times 3 \times 10 \dfrac{1}{2}}}$

$\twoheadrightarrow{\sf{Area_{(\triangle)} = \dfrac{1}{2} \times 3 \times \dfrac{20 + 1}{2}}}$

$\twoheadrightarrow{\sf{Area_{(\triangle)} = \dfrac{1}{2} \times 3 \times \dfrac{21}{2}}}$

$\twoheadrightarrow{\sf{Area_{(\triangle)} = \dfrac{1 \times 3 \times 21}{2 \times 2}}}$

$\twoheadrightarrow{\sf{Area_{(\triangle)} = \dfrac{3 \times 21}{2 \times 2}}}$

$\twoheadrightarrow{\sf{Area_{(\triangle)} = \dfrac{63}{4} \: {m}^{2} }}$

$\twoheadrightarrow{\sf{Area_{(\triangle)} = 15\dfrac{3}{4} \: {m}^{2} }}$

$\star{\underline{\boxed{\sf{\red{Area_{(\triangle)} = 15\dfrac{3}{4} \: {m}^{2}}}}}}$

Hence, the area of triangle is $\bf{15\dfrac{3}{4}}$ m².

$\rule{300}{2.5}$