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3 years ago

X^2-3=5x simplify this

1 answer:

7 0

To simplify x^2-3 =5x

You would first subtract 5x from both sides

X^3-5x-3

Next you would plug this into the quadratic equation:

X=5+/- the square root of: -5^2 -4(1)(-3)/2(1)

Then simplify,
5+/- the squareroot of 24 + 12 / 2

5+/- The squareroot of 36 /2

5+/- 6 / 2

Then solve if it’s an addition or subtract

5+6/2

X=11/2 or 5 1/2

5-6/2

X= -1/2

The answer is x=-1/2 or x=11/2

Hope this helps

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1. A buoy floats 19 yards from the eastern most point of a boat and 15 yards from the western most point of a second boat. The a

Black_prince [1.1K]

The laws of cosines and law of sines can be used given that two sides

and an included angle, or two angles a side are known.

Response:

1. The other angles in the triangle formed by the buoy are approximately;

31.1° and 40.9°

2. Distance of the helicopter from the first island is approximately;

14.5 miles

<h3>How is the Law of Sines and Cosines used?</h3>

Given parameters are;

Distance of the buoy from the easternmost point of a boat = 19 yards

Distance of the buoy from the westernmost point of the other boat = 15 yards

Angle formed from the buoy to the two boats = 108°

Distance between the two boats, d, is given by the law of cosines, as follows;

d² = 19² + 15² - 2 × 19 × 15 × cos(108°) = 586 - 570·cos(108°)

d = √(586 - 570·cos(108°))

By the law of Sines, we have;

$\dfrac{d}{sin(108^{\circ})} = \mathbf{\dfrac{15}{sin(Angle \ formed \ from \ the \ boat \ on \ the \ West, \ \theta_1)}}$

Which gives;

$sin(\theta_1) = \mathbf{ \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} }}$

The o

$\theta_1 = arcsin \left( \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} } \right) \approx \mathbf{31.1^{\circ}}$

The other angles formed in the triangle containing the buoy are;

θ₁ ≈ 31.1

θ₂ ≈ 180° - 108° - 31.1° ≈ 40.9°

2. Distance between the two islands = 20 miles

Angle of elevation with one island = 15°

Angle of elevation with the second island = 35°

Required:

The mileage (distance travelled) of the helicopter.

Solution:

Let A represent the island that has an angle of elevation to the helicopter

of 15°, and let B represent the other island.

Angle formed by the helicopter and the two island, θ, is found as follows;

θ = 180° - (15° + 35°) = 130°

By the Law of Sines, we have;

$\dfrac{20}{sin(130^{\circ})} = \mathbf{ \dfrac{Distance \ from \ island \ A }{sin(35^{\circ})}}$

Which gives;

$Distance \ of \ helicopter \ from \ island \ A = \mathbf{ \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ})}$

$Mileage \ from \ island \ A = \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ}) \times cos(15^{\circ}) \approx 14.5$

The mileage of the helicopter from the first island is approximately 14.5 miles

Learn more about the Law of Sines and Cosines here:

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2 years ago

Carmen borrowed money from her sister. Each month she makes four payments , with an average payment of no more than $ 200 . This

cricket20 [7]

Answer:

$95

Step-by-step explanation:

We are told that Carmen makes a monthly payment of no more than 200 dollars. We then see her going above the 200 dollars so we look to the tens and ones place. We see that we now have 25, 45, and 35 dollars. Add them up and you get 105 dollars. 200-105=95 so your awnser is $95.

7 0

3 years ago

HELP ME PLEASE !!!!!!!!

vivado [14]

Answer:

I got 70% hope it helps man

4 0

3 years ago

a textbook company ships its books in boxes that can hold 30 pounds. one particular order calls for a shipment of 800 books. if

Pachacha [2.7K]

83 boxes are required to carry 800 books.

According to the question:

One Box can hold weight = 30 pounds

We know that , 1 pound= 0.45 kg

hence, 30 pounds = 30 x 0.45 = 13.5kg

hence, one box can carry 13.5 kg of weight.

Now,

Weight of 1 book = 1.4 kg

So, Total Weight of 800 books= 1.4 x 800 kg

And , No. of boxes required to carry 800 books = (1.4 x 800)/13.5 = 82.96

or approximately 83 boxes

Hence, 83 boxes are required to carry 800 books.

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2 years ago

Mrs. McClure's famous peanut butter cookies call for 1 cup of peanut butter for every 1 2 of a cup of oil. Today, she wants to m

bezimeni [28]

Answer:

Amount of butter need for 1 cup of oil = 2 cup of butter

Step-by-step explanation:

Given:

Amount of butter need for 1/2 cup of oil = 1 cup

Find:

Amount of butter need for 1 cup of oil

Computation:

Amount of butter need for 1/2 cup of oil = 1 cup

1 cup butter = 1/2 cup oil

So,

Amount of butter need for 1 cup of oil = 1 / [1/2]

Amount of butter need for 1 cup of oil = 1 / [0.5]

Amount of butter need for 1 cup of oil = 2 cup of butter

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3 years ago