the answer to this problem is 2/25. I got this by simplifying both exponents which changes the equation to (2)(1000)(4)(1/100000). Then you multiply the other numbers by its simplified exponent and makes the equation 2000(1/25000). The last step is to multiply those two and you get your answer, 2/25(simplified version) :)
Answer:
15th term = 116
Step-by-step explanation:
a= 4
Sum of an A.P = n/2 {2a + (n-1)d}
sum of first five term is equal to one-fourth of the sum of the next five term
5/2{ 2*4 + (5-1)d} = 1/4 × 10/2{2*4 + (10-1)d
5/2 {8 + 4d} = 1/4 × 5{ 8 + 9d}
40/2 + 20/2d = 1/4{ 40 + 45d)
20 + 10d= 40/4 + 45/4d
20 + 10d = 10 + 45/4d
20 - 10 = 45/4d - 10d
10 =45d - 40d /4
10 = 5/4d
Divide both sides by 5/4
10 ÷5/4 = d
10×4/5 = d
40/5 = d
8 = d
d= 8
Find the 15th term
15th term = a + (n-1)d
= 4 + (15-1)8
= 4 + (14)8
= 4 + 112
= 116
The 15th term is 116
Answer:
That's alot of words its kinda hard to understand
Answer:
The probability that an 18-year-old man selected at random is greater than 65 inches tall is 0.8413.
Step-by-step explanation:
We are given that the heights of 18-year-old men are approximately normally distributed with mean 68 inches and a standard deviation of 3 inches.
Let X = <u><em>heights of 18-year-old men.</em></u>
So, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z = 
~ N(0,1)
where, 
= mean height = 68 inches
= standard deviation = 3 inches
Now, the probability that an 18-year-old man selected at random is greater than 65 inches tall is given by = P(X > 65 inches)
P(X > 65 inches) = P( > 
) = P(Z > -1) = P(Z < 1)
= <u>0.8413</u>
The above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.8413.
