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pantera1 [17]
3 years ago
12

You have a choice to invest in one of three different college funds to save up for college. You need to save at least $14,000 fo

r your first year. In which of the three accounts do you choose to invest your money given that you have $10,000 to invest and you would like to accrue as much interest as possible?​

Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer: C) You choose account #2

===================================================

Explanation:

Let's compute the final balance for account 1.

We'll use the compound interest formula

A = P*(1+r/n)^(n*t)

where,

  • P = principal or amount deposited
  • r = decimal form of the annual interest rate
  • n = number of times we compound the interest per year
  • t = number of years

where in this case

  • P = 10,000
  • r = 0.035
  • n = 4
  • t = 10

So with all that in mind, we get

A = P*(1+r/n)^(n*t)

A = 10,000*(1+0.035/4)^(4*10)

A = 14,169.0883793113

A = 14,169.09

Account #1 gets us $14,169.09 which is over our goal of $14,000

--------------------------

Let's repeat this idea for account 3. I'll get back to account 2 in the next section.

For account 3, we have these inputs

  • P = 10,000
  • r = 0.032
  • n = 1
  • t = 10

leading to...

A = P*(1+r/n)^(n*t)

A = 10,000*(1+0.032/1)^(1*10)

A = 13,702.4104633564

A = 13,702.41

This isn't larger than 14,000. So we cannot use account 3. The interest rate is too small and needs to be bumped up.

--------------------------

Now let's compute account 2. We'll use the continuously compounded interest formula which is

A = P*e^(rt)

The P, r and t are the same as before. The 'e' is a constant and it's roughly e = 2.718... similar to how pi = 3.14... approximately.

I recommend using the calculator's stored value of 'e' to get as much accuracy as possible.

So,

A = P*e^(rt)

A = 10,000*e^(0.036*10)

A = 14,333.2941456052

A = 14,333.29

This exceeds 14,000 so we can use this account.

Comparing this to account 1's value (14,169.09), we can see that account 2 gets us the most money over the 10 year time period. Not only does account 2 have the higher interest rate, but it also has an infinitely higher compounding frequency as well. These two factors help contribute as to why account 2 beats out account 1.

This is why we should go for account 2.

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3 years ago
Correctly complete this sequence: 88511, 16351, ?, 10251
IgorC [24]

Answer:

73155 will be the 3rd number in the sequence: 88511, 16351, ?, 10251.

So, the complete sequence will be: 88511, 16351, 73155, 10251.

Step-by-step explanation:

As 88511 is the first number.

The number 88511 has a certain pattern that could help us finding the next number.

So, let us consider 88511 and determine the pattern to find the next number and so on to complete the sequence.

Adding the first 2 digits in the number 88511 i.e.  8 + 8 = 16

Subtracting the 3rd digit from the 2nd digit i.e. 8 - 5 = 3

Multiplying the 3rd digit and 4th digit i.e. 5 × 1 = 5

Dividing the 4th digit by the 5th digit i.e. 1 ÷ 1 = 1

Hence, using these steps would get us the number 16351.

So, the next number would obtained using same steps:

Adding the first 2 digits in the number 16351 i.e.  1 + 6 = 7

Subtracting the 3rd digit from the 2nd digit i.e. 6 - 3 = 3

Multiplying the 3rd digit and 4th digit i.e. 3 × 5 = 15

Dividing the 4th digit by the 5th digit i.e. 5 ÷ 1 = 5

Hence, using these steps would get us the number 73155.

So, the next number would obtained using same steps:

Adding the first 2 digits in the number 73155 i.e.  7 + 3 = 10

Subtracting the 3rd digit from the 2nd digit i.e. 3 - 1 = 2

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Dividing the 4th digit by the 5th digit i.e. 5 ÷ 5 = 1

Hence, using these steps would get us the final number 10251.

So, from this observation, we determine that 73155 will be the 3rd number<em> </em>in the sequence: 88511,16351,?,10251.

So, the complete sequence will be: 88511, 16351, 73155, 10251.

Keywords: sequence, number

Learn more about sequence from brainly.com/question/13257823

#learnwithBrainly

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Answer:

x=\boxed {3.5}

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∠ACD ≅ ∠BCD

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We know that, from angle bisector theorem that,

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\dfrac{AC}{BC} =\dfrac{AD}{DB}  

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