59 is a rational number
59 is not a irrational number because simply a irrational number is basically
Pi ,E
Or any imperfect squares
A irrational number is a non repeating decimal and has different numbers in each space
Answer:
1/2 or 50% probability
Step-by-step explanation:
There are just two players, player A and player B. Since it is between this two players, for player A to score first we would have:
AB where player A is the first player to score, we wouldn't have BA since player would not be the first here
Probability = number of favorable outcomes/total number of outcomes
Therefore probability of A being the first player = number of A/total number of players
=1/2 = 0.50
There is therefore a 50% chance of A being the first player
If you simplify what's in the bracket, you get 3n
=(3n)+4=32/2
=3n+4= 32/2(here we can either crossmultiply or equate)
3n+4-4=32/2-4(subtract 4 from both sides)
3n=32/2-4
3n=24/2
3n=12
3n=12(divide both sides by the coefficient of the unknown)
3n/3=12/3
n=4
I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs
are:
cos(x)tan(x) – ½ = 0
→ π/6 and 5π/6
cos(π/6)tan(π/6) – ½ = 0
cos(5π/6)tan(5π/6) – ½ = 0
sec(x)cot(x) + 2 =
0 → 7π/6 and 11π/6
sec(7π/6)cot(7π/6) + 2 = 0
sec(11π/6)cot(11π/6) + 2 = 0
sin(x)cot(x) +
1/sqrt2 = 0 → 3π/4 and 5π/4
sin(3π/4)cot(3π/4) + 1/sqrt2 = 0
sin(5π/4)cot(5π/4) + 1/sqrt2 = 0
csc(x)tan(x) – 2 = 0 → π/3 and 5π/3
csc(π/3)tan(π/3) – 2 = 0
csc(5π/3)tan(5π/3) – 2 = 0
