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2 years ago

What multiples together to give you -30 and adds together to give you -1?

Mathematics

2 answers:

Novay_Z [31]2 years ago

6 0

List the multiples of -30: -1,1,-2,2,-3,3,-5,5,-6,6,-10,10,-15,15,-30,30

now find the two that would add together to equal -1:

—6 + 5 = -1

-6 x 5 = -30

Answer: -6 and 5

Alex73 [517]2 years ago

4 0

-6 x 5 = -30
-6 + 5 = -1

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MaRussiya [10]

Step-by-step explanation:

I believe this would be A or D

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2 years ago

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

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3 years ago

Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 40% chan

azamat

Answer:

There are a 25% probability that Christine fails the course.

Step-by-step explanation:

We have these following probabilities:

A 50% probability that Christine finds a tutor.

With a tutor, she has a 10% probability of failling.

A 50% probability that Christine does not find a tutor.

Without a tutor, she has a 40% probability of failing.

Probability that she fails:

10% of 50%(fail with a tutor) plus 40% of 50%(fail without a tutor). So

$P = 0.1*0.5 + 0.4*0.5 = 0.25$

There are a 25% probability that Christine fails the course.

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3 years ago

Z-8-22<br> z equals what

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Answer:

z=30

Step-by-step explanation:

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Answer:

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