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Valentin [98]
3 years ago
5

one a windy moring a hot air balloon starts ascending and flying away from the too of a hill the alritude h(x) in feet of the ba

lloon x hours after starting its ascent can be modeled by the function h (x)= -16x^2 +56x+96. Of factoring to find the roots what would be the GREATEST common factor to pull out to begin??
Mathematics
1 answer:
makkiz [27]3 years ago
3 0

The greatest common factor of all the coefficients is of 8.

<h3>What is the greatest common factor?</h3>

The greatest common factor between multiple terms is the largest value for which all terms are divisible.

In this problem, the equation is:

h(x) = -16x^2 + 56x + 96

The terms are 16, 56 and 96. Hence, to find the gcf, we have to keep factoring them by prime factors while all can be factored by the same value, hence:

16 - 56 - 96|2

8 - 28 - 48|2

4 - 14 - 24|2

1 - 7 - 12

There are no terms by which both 7 and 12 are divisible, hence the procedure is stopped and:

gcf(16, 56, 96) = 2³ = 8.

You can learn more about the greatest common factor at brainly.com/question/26140769

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Use Pascal’s Triangle to expand the binomial. (8v+s)^5
il63 [147K]
<span>Pascal 's triangle is 
</span>

1<span>
</span><span><span>1,1</span><span>
</span></span><span><span>1,2,1</span><span>
</span></span><span><span>1,3,3,1</span><span>
</span></span><span><span>1,4,6,4,1</span><span>
</span></span><span>1,5,10,10,5,1</span>

the row <span>1,5,10,10,5,1</span> is the one we need to expand <span><span><span>(8</span>v+s)</span></span>⁵.

Given <span><span>(a+b)</span></span>⁵ each term of the row is the coefficient of akbt

with k goes form 5 to 0 and t goes from 0 to 5.

so <span><span><span><span>(a+b)</span></span></span></span>⁵=1a⁵b⁰+5a⁴b¹+10a³b²+10a²b³+5a¹b⁵+1a⁰b⁵

<span><span>=<span>a</span></span></span>⁵+5a⁴b+10a³b²+10a²b³+5ab⁵+b⁵.

In the case of <span><span><span>(8</span>v+s)</span></span>⁵:

<span><span>a<span>=8</span>v</span><span>
</span></span><span>b=s</span>

<span><span>1<span><span>(8</span>v)</span></span></span>⁵s⁰+5(8v)⁴s¹+10(8v)³s²+10(8v)²s³+5(8v)¹s⁵+1(8v)⁰s⁵

<span> <span><span><span>=<span><span> (8</span>v)</span></span></span></span>⁵+5(8v)⁴s+10(8v)³s²+10(8v)²s³+5(8v)s⁵+s⁵=</span>

<span><span><span>= 8</span></span></span>⁵v⁵+5⋅8⁴v⁴s+10⋅8³v³s²+10⋅8²v²s³+40vs⁵+s⁵=

<span><span><span>= 32768</span><span><span>v</span></span></span></span>⁵<span><span><span>+20480</span><span><span>v</span></span></span></span>⁴<span><span><span>s</span><span>+5120</span><span><span>v</span></span></span></span>³<span><span><span><span>s</span></span></span></span>²<span><span><span>+640</span><span><span>v</span></span></span></span>²<span><span><span><span>s</span></span></span></span>³<span><span><span>+40</span><span>v<span>s</span></span></span></span>⁵<span><span><span>+</span><span>s</span></span></span>⁵<span>.</span>
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