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2 years ago

Please may help to solve this a=3,b=1,c=0&d=2 solve; A^3-3A+I2

Mathematics

1 answer:

Oxana [17]2 years ago

8 0

Answer: 30 I guess?

Step-by-step explanation:

3^(3)= 27

3(3)= 9

so 27-9=18

18+12= 30

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Would like scatter plot image with line of best fit on the plot

dlinn [17]

Just take it in co-ordinate pairs

(x,y)=(Arm span,Height)

Take two points

(58,60)
(41,40)

Slope:-

$\\ \sf\longmapsto m=\dfrac{40-60}{41-58}$

$\\ \sf\longmapsto m=\dfrac{-20}{-17}$

$\\ \sf\longmapsto m=\dfrac{20}{17}$

$\\ \sf\longmapsto m\approx 1.2$

Equation of line in point slope form

$\\ \sf\longmapsto y-y_1=m(x-x_1)$

$\\ \sf\longmapsto y-60=1.2(x-58)$

$\\ \sf\longmapsto y-60=1.2x-69.6$

$\\ \sf\longmapsto 1.2x-y-9.6=0$

Convert to slope intercept form y=mx+b

$\\ \sf\longmapsto y=1.2x-9.6$

Graph attached

7 0

2 years ago

1. What is the ratio of black to white squares? (1 mark)<br> I

kati45 [8]

im sure it would be 2:4. if it was to be simplified it would be 1:2

6 0

2 years ago

Read 2 more answers

F(x) = 9x + 3<br>g(x) = 3x + 1<br>Find:<br>(f/g)(x)

igomit [66]

Answer:

Step-by-step explanation:

f(x) = 9x + 3

g(x) = 3x + 1

To find (f/g)(x) divide f(x) by g(x)

That's

$(f/g)(x) = \frac{9x + 3}{3x + 1}$

Factorize f(x)

f(x) = 9x + 3 = 3(3x + 1)

So we have

$(f/g)(x) = \frac{3(3x + 1)}{3x + 1}$

Simplify

We have the final answer as

Hope this helps you

4 0

2 years ago

What would be the least amount of money needed to purchase exactly 19 muffins?

Lady bird [3.3K]

B: 9.25

12/19=5.75/x
X=9.10 but least amount which is 9.25

7 0

1 year ago

Read 2 more answers

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago