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3 years ago

How do I put (-3,2) and (-2,-3) in slope formula

Mathematics

2 answers:

grin007 [14]3 years ago

3 0

Answer:

-5

Step-by-step explanation

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harina [27]3 years ago

3 0

The slope formula is

(y2-y1)/(x2-x1)

In the point (-3,2),

-3 is x and 2 is y

y2 represents the second y point, and y1 represents the first y point

same for x

so, its

(-3-2)/(-2-(-3))=

-5/1=

-5

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3 years ago

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ryzh [129]

Answer:

The answer is

$x = \frac{ - 9 - \sqrt{41} }{10} \: \: \: , \: \: \: \: \: \frac{ - 9 + \sqrt{41} }{10} \\$

Step-by-step explanation:

5x² + 9x + 2 = 0

Using the quadratic formula that's

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\$

From the question

a = 5 , b = 9 , c = 2

We have

$x = \frac{ - 9 \pm \sqrt{ {9}^{2} - 4(5)(2) } }{2(5)} \\ = \frac{ - 9 \pm \sqrt{81 -40 } }{10} \\ = \frac{ - 9 \pm \sqrt{41} }{10} \: \: \: \: \: \: \: \: \: \:$

We have the final answer as

$x = \frac{ - 9 - \sqrt{41} }{10} \: \: \: , \: \: \: \: \: \frac{ - 9 + \sqrt{41} }{10} \\$

Hope this helps you

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