Find the mean, median, and interquartile for the data set below. Round your answer to the nearest tenth. 27,16,8,5,19,14,22,31,1
slavikrds [6]
Mean: 15.92
Median: 26
interquartile range: 14-16
IQR is 99 so the last one
Answer:
m = 134 miles
Step-by-step explanation:
f(m) = 16.95 + 0.92m
140.23 = 16.95 + 0.92m
0.92m = 140.23 - 16.95
0.92m = 123.28
m = 123.28/0.92
m = 134 miles
Looking at the chart, we can see that with diet chow, the weight changed by -26, while with kitty diet, it changed by -13. Therefore, the Diet Chow was more effective
Gradient =
Change in Y
———————
Change in X
Change in Y is 18 - 14 = 4
Change in X is -20 - 30 = -50
Therefore the gradient is 4/-50 which is then simplified to - (2/25)
