What is the x intercept of 4x+6y=3x+8?

VARVARA [1.3K]

Answer:

<h2>The solution is -9 < x < 17.</h2>

Step-by-step explanation:

|x-4|<13.

The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.

Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.

7 0

3 years ago

A club began with 3 members. Each month, each member brought one new member. Which function can be used to determine the number

erastova [34]

In x th month, members = $3^{2x}$ . Option D.

Step-by-step explanation:

Given,

Initially number of members = 3

Every month each member brought 1 new member.

To find the number of members after x months.

<u>Solution:</u>

In 1st month, members = 3

In 2nd month, members = 3×3 = 9 = 3²

In 3rd month, members = 9×9 = 81 = $3^{4}$

In 4th month, members = 81×81 = 81 = 6561 = $3^{8}$

Hence,

In x th month, members = $3^{2x}$

3 0

3 years ago

How can you find the lateral area using the perimeter of the base and the height?

DENIUS [597]

You multiply the perimeter of the base by the height of the prism to get the lateral are or. LA=pB*H Lateral Area=perimeter of Base times Height

3 0

3 years ago

MATH HELP PLEASE !50 POINTS!

docker41 [41]

Answer: 108

Step-by-step explanation: You take the x and the 2/3x and combine them to get 1 2/3x, so 1 2/3x=180. 180 divided by 5 is 36, and 36 times three is 108

7 0

3 years ago

Read 2 more answers

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

3 years ago