What is the x intercept of 4x+6y=3x+8?

pychu [463]

Absolute value of function = - 9 / 3 .

The absolute value or modulus of a real number x, denoted by |x|, is the non-negative value of x without regard to its sign. Namely, |x|=x if x is a positive number, and |x|=-x if x is negative (in which case negating x makes -x positive) , and |0|=0.

For example, the absolute value of 3 is 3, and the absolute value of −3 is also 3. The absolute value of a number may be thought of as its distance from zero.

x ≥ 1.52 / 3 x - 1 = 2 / 3 x + 4⇒ -1 = 4 which is not possible .Now for all x ≤ 1.5- 2 /3 x + 1 = 2 / 3 x + 4⇒ 4 / 3 x = -3 x = - 9 /4 Hence absolute value = - 9 / 3 .

To learn more on absolute value follow link :

brainly.com/question/13041863

#SPJ9

8 0

1 year ago

WILL MARK BRAINLIEST IF CORRECT

Virty [35]

Answer:

5/6

Step-by-step explanation:

Its the only fraction that has 0.833333...

3 0

3 years ago

Read 2 more answers

Highland Park is located between two parallel streets, Walker street and James Avenue. The park faces Walker Street and is borde

ehidna [41]

Applying the definition of alternate angles and angles on a straight-line: m<ACB = 84°.

Recall:

Alternate angles are congruent and have equal angle measures.

Angles on a straight-line = 180 degrees.

The diagram showing the information and sketch of the Highland Park is attached below (see attachment).

Thus:

m<BAC = 36° (given)

m<BCE = 60° (given)

<ACD = <BAC (alternate angles)

Therefore,

m<ACD = 36°

m<ACB = 180° - (m<ACD + m<BCE) (angles on a straight-line)

Substitute

m<ACB = 180° - (36° + 60°)

m<ACB = 84°

Thus, applying the definition of alternate angles and angles on a straight-line: m<ACB = 84°.

Learn more here:

brainly.com/question/15234579

5 0

3 years ago

The opponents of soccer team A are of two types: either they are a class 1 or a class 2 team. The number of goals team A scores

NikAS [45]

Answer:

a) The expected number of goals team A will score is 5.1

b) The probability that team A will score a total of 5 goals is 0.1147

Step-by-step explanation:

Let X be the amount of goals scored by team A in both matches. Let X1 and X2 be the total amount of goals team A scores in match 1 and 2 respectively, then X = X1+X2, and also

a)

E(X) = E(X1+X2) = E(X1)+E(X2) = 0.6*2+0.4*3 + 0.3*2+0.7*3 = 5.1

b) In order for X to be equal to 5 we have 5 possibilities

- X1 is 0 and X2 is 5

- X1 is 1 and X2 is 4

- X1 is 2 and X2 is 3

- X1 is 3 and X2 is 2

- X1 is 4 and X2 is 1

- X1 is 5 and X2 is 0

Let T1 be a poisson distribution with mean λ = 2, then

$P(T1=0) = e^{-2}$

$P(T1=1) = 2 * e^{-2}$

$P(T1=2) = 2 * e^{-2}$

$P(T1=3) = \frac{4}{3} \, e^{-2}$

$P(T1=4) = \frac{2}{3}\, e^{-2}$

$P(T1=5) = \frac{4}{15}\,e^{-2}$

Lets do the same with a Poisson distribution T2 with mean λ = 3

$P(T2=0) = e^{-3}$

$P(T2=1) = 3 \, e^{-3}\\P(T2=2) = \frac{9}{2} \, e^{-3}\\P(T2=3) = \frac{9}{2} \, e^{-3}\\P(T2=4) = \frac{27}{8} \, e^{-3}\\P(T2=5) = \frac{81}{40} \, e^{-3}$

Now, we are ready to compute the probability that X is equal to 5.

$P(X1 = 0, X2 = 5) = (0.6* e^{-2} + 0.4*e^{-3}) * (0.3*\frac{4}{15}e^{-2} + 0.7*\frac{81}{40} e^{-3}) = 0.00823\\P(X1 = 1, X2 = 4) = (0.6* 2e^{-2} + 0.4*3 e^{-3}) * (0.3*\frac{2}{3}e^{-2} + 0.7*\frac{27}{8} e^{-3}) = 0.03214\\P(X1 = 2, X2 = 3) = (0.6* 2e^{-2} + 0.4*\frac{9}{2}e^{-3}) * (0.3*\frac{4}{3}e^{-2} + 0.7*\frac{9}{2} e^{-3}) = 0.05317\\P(X1 = 3, X2 = 2) = (0.6* \frac{4}{3}e^{-2} + 0.4*\frac{9}{2}*e^{-3}) * (0.3*2e^{-2} + 0.7*\frac{9}{2} e^{-3}) = 0.0471$

$P(X1 = 4, X2 = 1) = (0.6* \frac{2}{3}e^{-2} + 0.4*\frac{27}{8}e^{-3}) * (0.3*2e^{-2} + 0.7*3e^{-3}) = 0.0225\\P(X1 = 5, X2 = 0) = (0.6* \frac{4}{15}e^{-2} + 0.4*\frac{81}{40}e^{-3}) * (0.3*e^{-2} + 0.7*e^{-3}) = 0.0047$

We can conclude that

P(X = 5) = 0.00823+0.03214+0.05317+0.0471+0.0225+0.0047 = 0.1147

The probability that team A will score a total of 5 goals is 0.1147

7 0

3 years ago

What is the probability of rolling a multiple of 5

givi [52]

Answer:

since you didn't give us a range, the possibility is infinity as there is no specified number of sides, and that answer doesn't really help. please be more specific in your future questions.

if the die has 6 sides, the probability of rolling a multiple of 5 is 1/6.

5 0

2 years ago