Answer:
yes
Step-by-step explanation:
Answer:
Ten hundredths in standard from is 0.1.
Answer:
2) Right angles always equal 90°
3) m∠F = 90° and m∠G = 90° which means they have the same angle measure.
4) Removing the m and replacing with the congruent symbol.
I'm not too sure how this goes but it should be something like that.
The solution to the given expression negative four and one third ÷ two and one fifth is -1 32/33
<h3>Fraction division</h3>
negative four and one third ÷ two and one fifth
-4 1/3 ÷ 2 1/5
= -13/3 ÷ 11/5
- Multiply by the reciprocal of 11/5
- The reciprocal of 11/5 is 5/11
= -13/3 × 5/11
= (-13 × 5) / (3 × 11)
= -65 / 33
= -1 32/33
Therefore, the solution to the fraction is -1 32/33
Learn more about fraction:
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Answer:
r(t) and s(t) are parallel.
Step-by-step explanation:
Given that :
the lines represented by the vector equations are:
r(t)=⟨1−t,3+2t,−3t⟩
s(t)=⟨2t,−3−4t,3+6t⟩
The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.
NOTE:
Two lines will be parallel if 
here;

Thus;



∴

Hence, we can conclude that r(t) and s(t) are parallel.