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3 years ago

If the sum of the squares of the two legs of a triangle does not equal the square of the third side, what can you conclude?

Mathematics

1 answer:

Masja [62]3 years ago

7 0

Answer:

The triangle is not right angled.

Step-by-step explanation:

According to the Pythagoras theorem, the sum of the squares of the two legs of a triangle is equal the square of the third side.

For example, in triangle ABC,

$AB^{2} = BC^{2}+CA^{2}$

It shows, that the triangle ANBC is right angled and right angle is at C.

So if the sum of the squares of the two legs of a triangle does not equal the square of the third side, it shows that the triangle is not right angled.

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I need to complete the equation of the line through (3 -1) and (4 7). I am really stumped on this topic, please explain the proc

Nana76 [90]

Assuming you want the equation in slope intercept form, you first need to use slope formula to find the slope.

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Plug in the coordinates that you have, (3,-1) and (4,7), for the x and y values respectively.

$\frac{-1-7}{3-4}$

Which reduces to 8/1=8.

The slope of your equation is 8.

Slope intercept form is: y=mx+b. m is your slope and b is your y-intercept, x and y stay unchanged.

Plug the slope in:

y=8x+b.

Now, you can plug one of the sets of coordinates into the x and y of the equation to find b. I'm using (3,-1).

-1=8(3)+b

-1=24+b

Subtract 24 from both sides.

-25=b

Now plug this into the equation!

y=8x-25 is your final equation.

I hope this helps :)

6 0

3 years ago

The sum of 1 and 7 times a number is 64. write and solve an equation to determine the number. select the solution and graph that

vichka [17]

x = 8, 1 + 7 +8 and 8 x 8 equals 64. good luck!

3 0

3 years ago

Read 2 more answers

Write an expression of the calculation of the products of five and two and five and one

lana [24]

(5)(2)(5)(1) could be an answer

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4 years ago

What is the range of the following function:<br> y = 2(5^x) - 1

Orlov [11]

<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

Range: (2,∞+)

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

$y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)$

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!