Answer:
Step-Question: The amount of money spent weekly on cleaning, maintenance, and repairs at a large restaurant was ...
The amount of money spent weekly on cleaning, maintenance, and repairs at a large restaurant was observed over a long period of time to be approximately normally distributed, with mean ? = $615 and standard deviation ? = $38.
(a) If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount? (Round your answer to four decimal places.)
(b) How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only0.08? (Round your answer to the nearest dollar.)
$by-step explanation:
Answer:
200
Step-by-step explanation:
To find the answer, we can first find the age of Rolando in four year:
17+4
=21
We can then proceed to find the current age of Marisa,which is 3/2 of Rolando’s age calculated above:
Let Marisa’s age be y.
3/2 y =21
y = 21 × 2/3
y = 42/3
y = 14
Therefore Marisa is currently 14 years old.
In three years, Marisa would be:
14+3
=17
Therefore, she will be 17 years old.
Hope it helps!
Answer: 325/790 rounded to the nearest hundredths place is <em>0.41</em>
Step-by-step explanation:
if you divide 325/790 you get 0.411 and some other numbers. We only need to focus on these 3 numbers. 4 is the tenths place value and the first 1 is in the hundredths place value. Sense the second 1 (which is in the thousandths place value) is less than 5, we don't round the 1 in the hundredths place value up. Meaning your answer is 0.411.
Hopefully this makes sense.
Answer:
13 and 16
Step-by-step explanation:
let the 2 parts be x and y, then
x + y = 29 → (1) and
x² + y² = 425 → (2)
From (1) → x = 29 - y → (3)
substitute x = 29 - y into (2)
(29 - y)² + y² = 425 ( expand factor )
841 - 58y + y² + y² = 425 ( rearrange into standard form )
2y² - 58y + 416 = 0 ← in standard quadratic form
divide all terms by 2
y² - 29y + 208 = 0
Consider the factors of 208 which sum to - 29
These are - 13 and - 16, hence
(y - 13)(y - 16) = 0
equate each factor to zero and solve for y
y - 13 = 0 ⇒ y = 13
y - 16 = 0 ⇒ y = 16
substitute these values into (3)
x = 29 - 13 = 16 and x = 29 - 16 = 13
The 2 parts are 13 and 16
