How to solve a log equation with variable in the exponent?
1 answer:
Example...
4^x = 16
log(4^x) = log(16)
x*log(4) = log(16)
x = log(16) / log(4)
You might be interested in
Answer:2*2=4
4^3=4*4*4=64
Step-by-step explanation:
Answer:
If your talking about the containers, then you would need 80
containers, hope this helps.
Step-by-step explanation:
x + 75 + x + 125 = 180
2x = 180-75-125
2x = -20
x = -10
(9x^4-13x^3-x-7)+(7x^3-2x+1)=
9x^4-13x^3-x-7+7x^3-2x+1=
9x^4+(-13+7)x^3+(-1-2)x-7+1=
9x^4+(-6)x^3+(-3)x-6=
9x^4-6x^3-3x-6
Answer: Option <span>D.)9x^4−6x^3−3x−6</span>
Step-by-step explanation:
answer= 8
I hope it's help uhh