All categories

3 years ago

Pls help it is due today

Mathematics

2 answers:

Serga [27]3 years ago

6 0

Answer:it increased

Step-by-step explanation:

a_sh-v [17]3 years ago

4 0

It increased that all

You might be interested in

I will do anything plss asppp

AlexFokin [52]

Answer:

I think the answer is A

Step-by-step explanation:

Let me know if it is not

4 0

3 years ago

The diameter of a cylindrical construction pipe is 4ft If the pipe is 17ft long, what is its volume? Use the value 3.14 for /pi,

Leya [2.2K]

Answer:

213.52 cubic ft

Step-by-step explanation:

Diameter of pipe = 4ft

radius for circle is half of diameter

thus radius of pipe = 1/2 of 4ft = 2 ft

length of pipe = 17 feet

volume of cylinder is given by $\pi r^2l$

where r is the radius and l is the length of cylinder

thus volume of pipe is calculated below using above values

$volume \ of \ pipe = \pi r^2l\\volume \ of \ pipe = \3.14* 2^2*17 \\volume \ of \ pipe = 213.52$

volume of pipe is 213.52 cubic ft.

5 0

3 years ago

let's write a 7 digit number.Increase this number by 10 lakh in each case and write next three numbers.

Tasya [4]

Answer:

next three digit is 45 and 7

Step-by-step ex:

hope this helps:)

7 0

3 years ago

Find the coordinates of the image of the point (3, 4) after it has been rotated by 180 degrees

sammy [17]

Answer:

(-3,-4)

Step-by-step explanation:

Flip the coordinate across the graph since it is 180 degrees. (x,y) becomes

(-x,-y)

6 0

3 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$

Thus the solution is found

5 0

3 years ago