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2 years ago

What kind of symmetry does a B have

1 answer:

4 0

The rest of the letters, A, B, C, D, and E all have only 1 line of symmetry. Notice that the A has a vertical line of symmetry, while the B, C, D, and E have a horizontal line of symmetry.

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All rectangles are parallelograms. A. True B. False

Amanda [17]

Answer: True

Step-by-step explanation:

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2 years ago

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Help me plsss....

eimsori [14]

Answer:

If it took the motorcycle 2 hours to cover 20km, then the average speed is 10km per hour.

Speed is equal to distance over time. So 20km divided by 2 hours is 10 km per hour.

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2 years ago

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The function y = f (x) is graphed below. What is the average rate of change of the function f(x) on the interval - 1 ≤ x ≤ 3?

jonny [76]

Answer:

$\displaystyle -2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Average Rate of Change: $\displaystyle \frac{f(b) - f(a)}{b - a}$

Step-by-step explanation:

Step 1: Define

Interval -1 ≤ x ≤ 3

a = -1, b = 3

f(a) = f(-1) = 4

f(b) = f(3) = -4

Step 2: Find Average

Substitute in variables [ARC]: $\displaystyle \frac{f(3) - f(-1)}{3 + 1}$
Substitute: $\displaystyle \frac{-4 - 4}{3 + 1}$
[Fraction] Subtract/Add: $\displaystyle \frac{-8}{4}$
[Fraction] Divide: $\displaystyle -2$

4 0

2 years ago

Suppose we describe the weather as either hot (Upper H) or cloudy (Upper C). Answer parts (a) and (b) below.

Ket [755]

Answer:

{HH,CC,HC,CH}

Step-by-step explanation:

We are given that

H denotes hot and cloudy denotes C.

We have to find the total possible outcomes for the weather on two consecutive days.

The possible cases in two consecutive days

Both days are hot=HH

Both days are cloud=CC

First day is hot other day cloudy=HC

First day is cloudy other day is hot=CH

Total possible cases=HH,CC,HC,CH

Therefor, the total outcomes for the weather on two consecutive days={HH,CC,HC,CH}

4 0

2 years ago

Q26. Meena bought a cake and left it on the table in the morning. When she came home in the evening, she saw that of the cake ha

Gwar [14]

The answer is; 24/75 of the entire cake remained

If 2/5 of the initial cake was eaten, the 3/5 is what remained

MInu ate 1/3 of the 3/5 = 3/15

3/5 – 3/15 = 6/15 remained

Her brother ate; 1/5 of 6/15 = 6/75

6/15 – 6/75 = 24/75 remained

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2 years ago