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3241004551 [841]
2 years ago
15

Match each graph with the correct equation written in standard form. Explain your reasoning.

Mathematics
1 answer:
My name is Ann [436]2 years ago
5 0

The graphs and their equations are:

  • Line 1: 6x - 2y = -10
  • Line 2: 9x - 9y = -45
  • Line 3: 3x - 12y = -60

<h3>How to determine the equations of the graphs</h3>

The three lines are linear equations, because they are all straight lines.

Also, the lines have the same y-intercept (this is so, because they cross the y-axis at the same point), but they have the same slope

Next, we rewrite the equations in slope-intercept form.

So, we have:

3x - 12y = -60

Divide through by -12

-0.25x +y = 5

Make y the subject

y = 0.25x + 5

6x - 2y = -10

Divide through by 2

3x - y = -5

Make y the subject

y = 3x + 5

9x - 9y = -45

Divide through by -9

-x + y = 5

Make y the subject

y = x + 5

Line 1 has the highest slope, while line 3 has the least slope.

So, we have the following equations:

  • Line 1: 6x - 2y = -10
  • Line 2: 9x - 9y = -45
  • Line 3: 3x - 12y = -60

Read more about linear equations at:

brainly.com/question/14323743

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What is the order of the set A={-1,20,3,17,5}
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Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~

I'm assuming your talking about least to greatest, OR greatest to least.  If so, that's what I'll do...


Least to Greatest: -1, 3, 5, 17, 20

Greatest to Least: 20, 17, 5, 3, -1

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A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of
professor190 [17]

The fuel consumption of each of the cars during the week are as follows;

  • The first car consumes <u>20 gallons of fuel</u>.
  • The second car consumes <u>30 gallons of fuel</u>.

Reasons:

Fuel efficiency of the first car = 15 miles per  gallon

Fuel efficiency of the second car = 35 miles per gallon

Combined distance traveled by the two cars in a week = 1,350 miles

The total gas consumption during the week = 50 gallons

Let <em>x</em> represent the number of gallons consumed by the first car, and let <em>y</em>

represent the number of gallons consumed by the second car, we get the

following system of simultaneous equations;

  • 15·x + 35·y = 1,350...(1)
  • x + y = 50...(2)

Therefore;

y = 50 - x

Which gives;

15·x + 35 × (50 - x) = 1,350

15·x + 1,750 - 35·x = 1,350

1,750 - 1,350 = 35·x - 15·x = 20·x

400 = 20·x

x = 400 ÷ 20 = 20

  • The number of gallons consumed by the first car, x = <u>20 gallons</u>

From equation (2), we have;

x + y = 50

y = 50 - x

Therefore;

y = 50 - 20 = 30

  • The number of gallons consumed by the second car, y = <u>30 gallons</u>

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