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lianna [129]
3 years ago
6

A model rocket is launched with an initial upward velocity of201ft/s . The rocket's height h (in feet) after t seconds is given

by the following. h=201t -16t^2
Find all values of for which the rocket's height is 93 feet.

Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)



...?
Mathematics
1 answer:
Rasek [7]3 years ago
4 0
3926 feet high per seconds
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sergejj [24]

Answer:

Step-by-step explanation:

Find the slope and then the equation of line.

(x₁ , y₁) = (2 , 2)   & (x₂, y₂) = (6 , 10)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

        = \frac{10 - 2}{6 - 2}\\\\= \frac{8}{4}\\\\= 2

m = 2

Equation of the line: y - y₁  = m(x - x₁)

              y - 2 = 2 (x - 2)

              y - 2 = 2x - 4

                   y = 2x - 4 + 2

                  y = 2x - 2  --------------(I)

(a, 8)  

Plug in x = a & y = 8 in (I)

8  = 2a - 2

8 + 2 = 2a

10   = 2a

a = 10/2

a = 5

(4 , b)

Plug in x = 4 & y = b in (I)

b = 2*4 - 2

b = 8 - 2

b = 6

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3 years ago
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4 years ago
Tobin rows 2 miles per hour faster than her opponent. If it takes Tobin 30 minutes to finish a race, and it takes her opponent 4
Sunny_sXe [5.5K]
If we represent Tobin's speed as x, we can write her opponent's speed as 
x-2 (since Tobin is 2 more than them). In addition, since it's in miles per hour, and 45 minutes is 3/4 of an hour, we can say that 3/4ths of her speed in miles per hour is how long the race is, so (3/4)(x-2)=distance of race. In addition, since it only took Tobin 30 minutes, and 30 minutes is half an hour, x/2 (half of her miles per hour) is the length of the race, so (3/4)(x-2)=(1/2)x. Expanding it, we get 3x/4-6/4=x/2. Subtracting x/2 (or 2x/4) from both sides, we get x/4-6/4=0 and by adding 6/4 to both sides we get x/4=6/4. Multiplying 4 to both sides, we get that x=6=Tobin's speed in miles per hour
6 0
4 years ago
State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle
DENIUS [597]

Answer:

The interval notation for the domain is [\frac{23}{3},\infty  ].

Step-by-step explanation:

Consider the provided information.

It is given that \:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7

We need to find the value of f\left(g\left(x\right)\right).

Put the value of g(x) in  f\left(g\left(x\right)\right).

f\left(g\left(x\right)\right)=f(x-7)  ....(1)

Now, put x=x-7 in \:f\left(x\right)=\sqrt{3x-2}

\:f\left(x-7\right)= \sqrt{3(x-7)-2}

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From equation 1.

f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}

The domain of the function is the set of input values for which a function is defined.

Here, the value of 3x-23 should be greater or equal to 0 as the square root of a negative number is not real.

Domain= 3x-23\geq0

x\geq\frac{23}{3}

The value of x is all real number greater than \frac{23}{3}.

Hence, the interval notation for the domain is [\frac{23}{3},\infty  ].

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KATRIN_1 [288]

Answer:

The slope is 0

Step-by-step explanation:

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19-19 / 8-(-6)

0 / 8+6

0/14

0

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3 years ago
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