Question

A fair die is cast, a fair coin is tossed, and a card is drawn from a standard deck of 52 playing cards. Assuming these events are independent, what is the probability that the number falling on the uppermost part of the die is a 6, the coin shows a head, and the card drawn is a face card? (Round your answer to 4 decimal places.)

Answer 1

Answer:

The probability is 0.0192 to four decimal places.

Step-by-step explanation:

In this question, we are asked to calculate the probabilities that three events will occur at the same time.

Firstly, we identify the individual probabilities.

The probability of 6 showing In a throw of die is 1/6

The probability of a coin showing head in a flip of coin is 1/2

The probability of a face card being drawn in a deck of cards is 12/52( There are 12 face cards in a deck of cards)

Mathematically to get the probability of all these events happening, we simply multiply all together.

This will be ;

1/6 * 1/2 * 12/52 = 1/52 = 0.0192 ( to 4 decimal place)

Answer 2

Answer:

0.0192 (Correct to 4 decimal places)

Step-by-step explanation:

For the Fair Die

Sample Space ={1,2,3,4,5,6}

n(S)=6

• P(The uppermost part of the die is a 6), $P(A) =\frac{1}{6}$

For the Coin

Sample Space ={Head, Tail}

n(S)=2

• P(The coin shows a head), $P(B) =\frac{1}{2}$

For the Card

n(S)=52 Cards

So, there are 13 cards of each suit. Among these 13 cards, there are 3 picture cards or face cards as they are called. These are the Jack, Queen and King cards.

Number of Picture Cards =12

• P(The card drawn is a picture card), $P(C) =\frac{12}{52}$

Since the events are independent,

$P(A \cap B \cap C)=P(A) \cdot P(B) \cdot P(C)$

$=\frac{1}{6}X \frac{1}{2}X\frac{12}{52}\\=0.0192$

Therefore, the probability that the number falling on the uppermost part of the die is a 6, the coin shows a head, and the card drawn is a face card is 0.0192 (Correct to 4 decimal places).