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IRINA_888 [86]
3 years ago
8

50 POINTS AND BRAINLIEST IF YOU ANSWER CORRECTLY.

Biology
1 answer:
klio [65]3 years ago
4 0

Answer:

none of the males or females could be colorblind, assuming that this question is referring to x-linked recessive inheritance patterns.

Explanation:

if it is an x linked recessive trait, then the male's genotype is, with (b) representing colorblindness and (B) representing normal vision. the female, who is h o m o z y g o u s for normal vision, would have the genotype.

It would be impossible for the dad to pass on his colorblind gene to a son, because he can only pass a Y chromosome to the son. and a daughter would get the colorblind gene, but the normal gene donated by the mom would dominate it so the daughter could not actually be colorblind

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b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr

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. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.

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Download docx
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