Find the measure of a negative angle coterminal with 60

Debroah earns $10 per hour tutoring other students in math class. she earns versus the time that she tutors for. on the lines be

vesna_86 [32]

It represents that she tutored for 0 hours, and earned $0.

3 0

3 years ago

In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

Viktor [21]

Answer:

$p_v =P(t_{(63)}>2.5)=0.0075$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=45$ represent the mean height for the sample

$s=16$ represent the sample standard deviation for the sample

$n=64$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=64-1=63$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(63)}>2.5)=0.0075$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

6 0

3 years ago

The fox population in a certain region has a continuous growth rate of 6 percent per year. It is estimated that the population i

Ksivusya [100]

Answer:

P(t) = 9800(1.06)^t

P(8) = 15620

Step-by-step explanation:

For growth the equation is

y = ab^x where a is the initial value, b = 1 plus the growth percentage, and x is the number of years

P(t) = 9800 (1+.06) ^t

P(t) = 9800(1.06)^t

from 2000 to 2008 is 8 years

P(8) = 9800(1.06)^8

15619.71113040224768

We can only have whole foxes

P(8) = 15620

3 0

2 years ago

Help asap !………………………

My name is Ann [436]

Answer:

c

Step-by-step explanation:

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4 0

1 year ago

Andre constructs the image of line n under a dilation centered at point O that is not on line n. Becca construct a different ima

GenaCL600 [577]

<em /><u><em /></u>I think that both lines will show only 1 line because 1 line will be on top of the other. I believe this because both lines are dilated with its center at point O which does not lie on line n. Whatever dilation Andre uses may also be the dilation used by Becca since their lines centered at point O. Both lines will have the same slope and share the same coordinates.

6 0

3 years ago