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zhannawk [14.2K]

3 years ago

6

Need Help solving this , pic of question

1 answer:

Mama L [17]3 years ago

7 0

<h3>Answer:</h3>

Length: 12 yd

Width: 5.5 yd

<h3>Explanation:</h3>

Let x represent the width of the rectangle in yards. Then 2x+1 can represent the length (double the width plus 1 yard). The area is the product of length and width so we have the relation ...

... x(2x+1) = 66

... 2x² +x -66 = 0

This can be solved using any of several methods. One of them is to factor the equation. To do that, we can look for factors of 2·66 = 132 that differ by 1. Since 132 = 11·12, those are the numbers we're looking for. Then ...

... 2x² +12x -11x -66 = 0 . . . . use our found numbers to rewrite the x term

... 2x(x +6) -11(x +6) = 0 . . . . .factor by grouping

... (2x -11)(x +6) = 0

... x = 11/2 or -6 . . . . . values that make the factors zero. Only the positive value is a useful solution.

... The width of the rectangle is 5.5 yards. Its length is 2·5.5+1 = 12 yards,

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lina2011 [118]

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3 years ago

Read 2 more answers

A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.

vichka [17]

Answer:

$14878.04878miles/hours^2$

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

$A=(Vf-Vi)/T$ where:

A=acceleration rate

Vf=final velocity

Vi=initial velocity

T=time required for passing from Vi to Vf.

Using the problem's data we have:

Vf=65miles/hour

Vi=6miles/hour

T=14.8seconds

Using the acceleration rate equation we have:

$A=(65miles/hour - 6miles/hour)/14.8seconds$ , but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

$X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)$

$X=0.0041hours$

Using X=0.0041hours in the previous equation instead of 14.8seconds we have:

$A=(65miles/hour - 6miles/hour)/0.0041hours$

$A=(61miles/hour)/0.0041hours$

$A=(61miles)/(hour*0.0041hours)$

$A=61miles/0.0041hours^2$

$A=14878.04878miles/hours^2$

In conclusion, the acceleration rate is $14878.04878miles/hours^2$

7 0

3 years ago

Can someone help me plz

koban [17]

inaccurate

3 less than would be x-3, but 3-x would be 3 more

6 0

2 years ago

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Artemon [7]

The answer is 3 square units

8 0

2 years ago

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mario62 [17]

The answer should be A. 4 Meters

5 0

2 years ago