Answer:
1st Graph
Step-by-step explanation:
A simple way to test if a relation may be taken as a function is by applying the Vertical Line Test. If a Vertical Line crosses the graph only once, then it is a function. In this question, only the first one can be considered to be a function.
Because in other words, only the first graph shows one value for x corresponding to another for y value. Not the case for the second and the third graph displaying two values for x for each y value.
The software rendering this question really butchered it... I think it's saying the displacement vector for the particle is
Differentiate twice with respect to time 
to get the velocity and acceleration vectors, respectively:
Then at 
, the acceleration of the particle is
which most closely resembles the first choice.
It is the transformation shown in (B)
(look at one point of the letter P and how it moves precisely 3 units. Also there is only the move, no flipping of the figure)
Answer:
R
Step-by-step explanation:
Apply the knowledge of CPCTC (corresponding parts of congruent triangles are congruent) to this
C and R are written last, and order is important, because they are congruent
If you do 240/2, you will get 120.
